我有一个对象数组,我想根据数组中对象的属性将其分解为另一组数组。
例如,我有一些这样的对象:
function Object1(property1, property2, property3){
this.property1 = property1;
this.property2 = property2;
this.property3 = property3;
}
然后,我有一个包含其中几个对象的数组,但是有些对象共享property1
的相同值,例如:
const obj1 = new Object1(id_1, some_value_1, some_value_2);
const obj2 = new Object1(id_2, some_value_2, some_value_2);
const obj3 = new Object1(id_1, some_value_3, some_value_3);
const obj4 = new Object1(id_2, some_value_4, some_value_4);
var objectArray = [obj1, obj2, obj3, obj4];
现在给定这个数组,我想基于Object1.property1
创建新的数组,以便最终得到以下数组:
array1 = [obj1, obj3];
array2 = [obj2, obj4];
这无疑不是一项任务,但我无法想到。感谢您的投入。
有一两个警告:我不会总是知道objectArray有多大,我不知道该数组中有多少个对象共享一个属性,这意味着需要x个新数组。
答案 0 :(得分:1)
您可以使用reduce
按特定属性对对象进行分组:
function Object1(property1, property2, property3) {
this.property1 = property1;
this.property2 = property2;
this.property3 = property3;
}
const obj1 = new Object1('id_1', 'some_value_1', 'some_value_2');
const obj2 = new Object1('id_2', 'some_value_2', 'some_value_2');
const obj3 = new Object1('id_1', 'some_value_3', 'some_value_3');
const obj4 = new Object1('id_2', 'some_value_4', 'some_value_4');
const objectArray = [obj1, obj2, obj3, obj4];
const outputObj = objectArray.reduce((accum, obj) => {
const id = obj.property1;
if (!accum[id]) accum[id] = [];
accum[id].push(obj);
return accum;
}, []);
const [array1, array2] = Object.values(outputObj);
console.log(array1);
console.log(array2);

您还应注意不要混用const
和var
- 如果您要使用ES6,请始终使用const
(并且很少使用let
,当需要重新分配时。)
答案 1 :(得分:1)
为简单起见,我将内联创建数组和对象。
这将在两次通过中完成。首先,用prop1将prop2和prop3分组。然后,过滤掉每个组的唯一元素。
var things = [
{prop1: 1, prop2: 'a', prop3: 'b'},
{prop1: 2, prop2: 'b', prop3: 'b'},
{prop1: 1, prop2: 'c', prop3: 'c'},
{prop1: 2, prop2: 'd', prop3: 'd'}
];
var grouped = things.reduce(function (groups, thing) {
groups[thing.prop1] = groups[thing.prop1] || [];
groups[thing.prop1].push(thing.prop2);
groups[thing.prop1].push(thing.prop3);
return groups;
}, {});
/*
We are now grouped by prop1.
{
1: ["a", "b", "c", "c"],
2: ["b", "b", "d", "d"]
}
*/
var groupedAndUniq = Object.keys(grouped).reduce(function (groups, key) {
groups[key] = [...new Set(grouped[key])];
return groups;
}, {});
console.log(groupedAndUniq);
/*
We are now grouped and unique.
{
1: ["a", "b", "c"],
2: ["b", "d"]
}
*/
答案 2 :(得分:0)
您可以使用.filter()
根据属性值选择数组中的对象:
function Object1(property1, property2, property3) {
this.property1 = property1;
this.property2 = property2;
this.property3 = property3;
}
const obj1 = new Object1(1, 'a', 'A');
const obj2 = new Object1(2, 'b', 'B');
const obj3 = new Object1(1, 'c', 'C');
const obj4 = new Object1(2, 'd', 'D');
const objectArray = [obj1, obj2, obj3, obj4];
const array1 = objectArray.filter(e => e.property1 == 1)
const array2 = objectArray.filter(e => e.property1 == 2)
console.log(array1)
console.log(array2)