R

Question

我试图在R中格式化我的数据，以便我可以正确地将它用于不同的一般线性模型。

数据是这样的：

> str(data)
'data.frame':   1978 obs. of  7 variables:
 $ country                : Factor w/ 22 levels "AT","BE","CH",..: 8 8 8 8 8 8 8 8 8 8 ...
 $ age                    : num  65 77 36 28 23 15 75 20 44 73 ...
 $ gender                 : Factor w/ 2 levels "male","female": 2 1 1 1 2 2 1 2 2 1 ...
 $ education_level        : Factor w/ 6 levels "less_than_lower_sec",..: 5 1 3 5 5 2 1 3 3 5 ...
 $ good_citizen_importance: Factor w/ 11 levels "00","01","02",..: 11 9 9 9 10 10 7 10 10 9 ...
 $ trade                  : Factor w/ 7 levels "none_apply","member",..: 2 4 4 2 2 4 4 4 2 4 ...
 $ relig                  : Factor w/ 7 levels "none_apply","member",..: 2 2 4 4 4 4 2 5 4 4 ...

数据本身的片段：

> head(data)
      country age gender     education_level good_citizen_importance   trade   relig
13711      FI  65 female            tertiary                      10  member  member
13712      FI  77   male less_than_lower_sec                      08 donated  member
13713      FI  36   male           upper_sec                      08 donated donated
13714      FI  28   male            tertiary                      08  member donated
13715      FI  23 female            tertiary                      09  member donated
13716      FI  15 female           lower_sec                      09 donated donated

我已经设法做了这种频率计数，这意味着我几乎就在那里。但我想得到所有因素和相关数量＆＃34; good_citizen_importance＆＃34;变量到列。

> counts <- count(data, c("good_citizen_importance", "trade", "relig", "gender"))
> head(counts)
  good_citizen_importance   trade   relig gender freq
1                      00 donated  member   male    1
2                      00 donated donated   male    1
3                      01  member donated female    1
4                      01 donated donated   male    2
5                      01 donated donated female    1
6                      02  member  member female    1  

这就是我想要的数据：

> head(counts)
    trade   relig   gender "00" "01" "02" ...
1   donated member  male     1    5    7   ...
2   donated donated male     12   2    3   ...
3   member  donated female   11   3    1   ...
4   donated donated male     25   1    4   ...
5   donated donated female   12   1    1   ...
6   member  member  female   11   1    1   ...

因此，我希望将一个变量的所有因子的因子频率与其他变量的组合结合起来。换句话说，＆＃34; good_citizen_importance＆＃34;的所有11个因子的频率列。变量

我确定这不是一个非常难的问题，但我已经打了好几个小时了，我觉得我现在已经用尽了我的R和Google技能。

Answer 1

这可以通过重塑数据来实现。在基础R中，可以使用函数reshape，但语法很笨拙（我以前经常使用它，我必须每次查找语法）。 spread套件中的tidyverse更好的解决方案（具体来说，它位于tidyr包中：

library(tidyr) # or library(tidyverse)
counts_wide <- counts %>% 
  spread(good_citizen_importance, freq, fill = 0)

如果您不熟悉管道运算符（%>%），它将获取前一个函数的输出并将其设置为下一个函数的第一个参数。它用于通过删除大量嵌套函数使代码更容易阅读。