我是Flutter的新手并且玩弄它。所以,请耐心等待我。
单击PopupMenuButton的特定菜单项时会抛出以下异常,但始终只是第二次:
'包:flutter / src / widgets / navigator.dart':失败的断言:行 1846 pos 12:'!_ debugLocked':不是真的。
这里的设置:
用于指定已定义类之后的菜单项:
class PopupMenuChoice {
const PopupMenuChoice({this.title, this.pageRoute});
final String title;
final MaterialPageRoute pageRoute;
}
AppBar的actions属性中PopupMenuButton的定义:
new PopupMenuButton<PopupMenuChoice>(
itemBuilder: (BuildContext context) {
return _popupMenus.map((PopupMenuChoice choice) {
return new PopupMenuItem<PopupMenuChoice>(
value: choice,
child: new Text(choice.title),
);
}).toList();
},
onSelected: _popupMenuSelected,
),
相应的小部件在下面的类中定义(AppBar在&#34中创建;返回新的脚手架&#34;此类):
class RandomWordsState extends State<RandomWords> {
final _suggestions = <WordPair>[];
final _saved = new Set<WordPair>();
final _popupMenus = <PopupMenuChoice>[];
...
}
正如您所看到的,有用于保存WordPair对象的私有变量,还有用于菜单选择的私有变量。
_popupMenus列表在&#34;构建覆盖&#34;中设置:
@override
Widget build(BuildContext context) {
// Setup page routes
if (_popupMenus.where((p) => p.title == 'Saved Suggestions').length == 0) {
final _pageRouteSavedSuggestions = new MaterialPageRoute(
builder: (context) {
final tiles = _saved.map(
(pair) {
return new ListTile(
title: new Text(
pair.asPascalCase,
style: _biggerFont,
),
);
},
);
final divided = ListTile
.divideTiles(
context: context,
tiles: tiles,
)
.toList();
return new Scaffold(
appBar: new AppBar(
title: new Text('Saved Suggestions'),
),
body: new ListView(children: divided),
);
},
);
_popupMenus.add(new PopupMenuChoice(
title: 'Saved Suggestions', pageRoute: _pageRouteSavedSuggestions));
}
if (_popupMenus.where((p) => p.title == 'TEST Page').length == 0) {
final _pageRouteTest = new MaterialPageRoute(
builder: (context) {
return new Scaffold(
appBar: new AppBar(
title: new Text('TEST Page'),
),
body: new Text('Some content...'),
);
},
);
_popupMenus.add(
new PopupMenuChoice(title: 'TEST Page', pageRoute: _pageRouteTest));
}
...
在PopupMenuChoice的定义的MaterialPageRoute中,私有变量可能是访问权限(例如_saved)。
这里是onSelected of PopupMenuButton的相应事件处理程序:
void _popupMenuSelected(PopupMenuChoice choice) {
Navigator.of(context).push(choice.pageRoute);
}
有人可以解释为什么会抛出这个异常吗?怎么可以预防?
谢谢, 罗杰
在特定菜单项上单击第二次时来自调试控制台的其他信息:
E / flutter(17133):[错误:topaz / lib / tonic / logging / dart_error.cc(16)] 未处理的异常:E / flutter(17133): &#39;包:flutter / src / widgets / routes.dart&#39;:失败的断言:第177行 pos 12:&#39;!_ transitionCompleter.isCompleted&#39;:无法安装 处理后的MaterialPageRoute。 E / flutter(17133):#0
_AssertionError._doThrowNew(dart:core / runtime / liberrors_patch.dart:37:39)E / flutter(17133):#1
_AssertionError._throwNew(dart:core / runtime / liberrors_patch.dart:33:5)E / flutter(17133):#2
TransitionRoute.install(包:flutter / src / widgets / routes.dart) E / flutter(17133):#3 ModalRoute.install (包:flutter / src / widgets / routes.dart:740:11)E / flutter(17133):#4 NavigatorState.push (包:flutter / src / widgets / navigator.dart:1444:11)E / flutter (17133):#5 RandomWordsState.build._popupMenuSelected (文件:/// d:/Flutter%20Projects/startup_namer/lib/main.dart:166:29) E / flutter(17133):#6
_PopupMenuButtonState.showButtonMenu。 (包:flutter / src / material / popup_menu.dart)E / flutter(17133):#7
_RootZone.runUnary(dart:async / zone.dart:1381:54)E / flutter(17133):#8 _FutureListener.handleValue(dart:async / future_impl.dart:129:18)E / flutter(17133):#9
Future._propagateToListeners.handleValueCallback (dart:async / future_impl.dart:633:45)E / flutter(17133):#10
Future._propagateToListeners(dart:async / future_impl.dart:662:32) E / flutter(17133):#11 Future._completeWithValue (dart:async / future_impl.dart:477:5)E / flutter(17133):#12
Future._asyncComplete。 (dart:async / future_impl.dart:507:7)E / flutter(17133):#13
_microtaskLoop(dart:async / schedule_microtask.dart:41:21)E / flutter(17133):#14 _startMicrotaskLoop (镖:异步/ schedule_microtask.dart:50:5)
答案 0 :(得分:1)
您尝试过吗:
void _popupMenuSelected(PopupMenuChoice choice) {
Navigator.push(context, choice.pageRoute);
}
答案 1 :(得分:0)
void _popupMenuSelected(PopupMenuChoice choice) {
await Future.delayed(const Duration(milliseconds: 100));
Navigator.push(context, choice.pageRoute);
}
答案 2 :(得分:0)
假设您有Auth Block, 那里你有 isLoggedIn = false; 以及发生登录网络呼叫的方法:
假设您设计这样的方法:
logIn(String userId,String Passwrod){
url ....
if(response.body == 200){
isLoggedIn = true ;
return response.body;
}
}
现在在您的Auth页面中:问题是:
在请求页面类时,您具有检查器:
(isLoggedIn){
Navigator.push(context, choice.pageRoute);
}
并且当用户单击“提交”按钮时,会出现以下内容:
(){
Navigator.push(context, choice.pageRoute);
}
现在的问题是您同时被调用,这意味着LoggedIn = true,然后此处的提交按钮响应就是问题。 删除首字母
(isLoggedIn){
Navigator.push(context, choice.pageRoute);
}
您的问题将得到解决。
将此检查器用于登录页面以外的其他页面