我正在建立一个国际象棋GUI,它应该与Stockfish交谈。我听说我必须生成一个FEN字符串,告诉Stockfish已经做出的举动。所以问题是,我该怎么做?我真的遇到了死胡同......我正在使用Eclipse IDE。
答案 0 :(得分:-1)
我不确定你做了什么或使用什么编程语言,但由于你使用的是Eclipse IDE,我建议它是Java。
使Stockfish工作的热门提示是观看此视频: https://www.youtube.com/watch?list=PLQV5mozTHmacMeRzJCW_8K3qw2miYqd0c&v=vuvTFNreykk
视频中链接的Stackoverflow:Using the Universal Chess Interface
所以要解决你的问题:
所以问题是,我该怎么做?
嗯,简单的解决方案是查找已经实现的FEN字符串项目。我知道他们中有很多。如果你想要一个简单的,又笨拙的在Java中制作FEN字符串的方法,我就这样做了:
注意:此实现认为您将整个电路板放在String [] []中(我没有在这些晚些时候使其更先进的麻烦)
注意2:它不会生成整个FEN字符串。它缺少活动颜色,Castling可用性,En passant,Halfmove时钟和Fullmove数字,但我确信您将能够轻松实现
输出:
rnbqkbnr / pppppppp / 8/8/8/8 / PPPPPPPP / RNBQKBNR
private final String RANK_SEPARATOR = "/";
private String[][] board = {
{"r","n","b","q","k","b","n","r"},
{"p","p","p","p","p","p","p","p"},
{"","","","","","","",""},
{"","","","","","","",""},
{"","","","","","","",""},
{"","","","","","","",""},
{"P","P","P","P","P","P","P","P"},
{"R","N","B","Q","K","B","N","R"}
};
public String translateBoardToFEN(String[][] board) {
String fen = "";
for (int rank = 0; rank < board.length; rank++) {
// count empty fields
int empty = 0;
// empty string for each rank
String rankFen = "";
for (int file = 0; file < board[rank].length; file++) {
if(board[rank][file].length() == 0) {
empty++;
} else {
// add the number to the fen if not zero.
if (empty != 0) rankFen += empty;
// add the letter to the fen
rankFen += board[rank][file];
// reset the empty
empty = 0;
}
}
// add the number to the fen if not zero.
if (empty != 0) rankFen += empty;
// add the rank to the fen
fen += rankFen;
// add rank separator. If last then add a space
if (!(rank == board.length-1)) {
fen += RANK_SEPARATOR;
} else {
fen += " ";
}
}
return fen;
}
答案 1 :(得分:-1)
我不想重复我的答案。请查看我发布的内容: