Question

代码：

 public class Dog{
        static int age;
        static String name;
        static String breed;
        public Dog(String name,int age,String breed){
            this.name=name;
            this.age=age;
            this.breed=breed;
        }
        public Dog(String name,int age){
            this(name,age,"greed");
        }
        public static void main(String args[]){
            Dog high=new Dog("luffy",19,"pomerian");
            Dog low=new Dog("gold",32,"german shepherd");
            System.out.println(low.name+" "+low.age+" "+low.breed);
            System.out.println(high.name+" "+high.age+" "+high.breed);
        }       
 }

输出： gold 32 german shepherd gold 32 german shepherd

虽然我正在创建两个对象实例，但只会打印其中一个对象的字段。这个错误在哪里？

Answer 1

所有static字段都是共享的（每个类static个字段），但您期望实例字段（每个实例）。变化

static int age;
static String name;
static String breed;

到

private int age;
private String name;
private String breed;

您应该拥有访问者（get ters）方法 - 如果添加toString()，您的打印将会简化。像，

@Override
public String toString() {
    return name + " " + age + " " + breed; 
}

然后你可以{/ 1}}只用

print

Answer 2

您已经为每个类对象使用了静态访问修饰符和静态变量共享内存。如果您不想要，那么只需从年龄，名称，品种中删除静态

public class Dog{
        int age;
        String name;
        String breed;
        public Dog(String name,int age,String breed){
            this.name=name;
            this.age=age;
            this.breed=breed;
        }
        public Dog(String name,int age){
            this(name,age,"greed");
        }
        public static void main(String args[]){
            Dog high=new Dog("luffy",19,"pomerian");
            Dog low=new Dog("gold",32,"german shepherd");
            System.out.println(low.name+" "+low.age+" "+low.breed);
            System.out.println(high.name+" "+high.age+" "+high.breed);
        }       
 }

Answer 3

在您的代码中将静态更改为私有：

示例：

 public class Dog{
            private int age;
            private String name;
            private String breed;
            public Dog(String name,int age,String breed){
                this.name=name;
                this.age=age;
                this.breed=breed;
            }
            public Dog(String name,int age){
                this(name,age,"greed");
            }


            }
            public static void main(String args[]){
                Dog high=new Dog("luffy",19,"pomerian");
                Dog low=new Dog("gold",32,"german shepherd");
                System.out.println(low.name+" "+low.age+" "+low.breed);
                System.out.println(high.name+" "+high.age+" "+high.breed);
            }       
     }

输出：

luffy 19 pomerian
gold 32 german shepherd

另外：

 public class Dog{
        private int age;
        private String name;
        private String breed;
        public Dog(String name,int age,String breed){
            this.name=name;
            this.age=age;
            this.breed=breed;
        }
        public Dog(String name,int age){
            this(name,age,"greed");
        }

        void toStrig (){
         System.out.println(name+" "+ age+" "+breed);
        }
        public static void main(String args[]){
            Dog high=new Dog("luffy",19,"pomerian");
            Dog low=new Dog("gold",32,"german shepherd");
            high.toStrig();
            low.toStrig();
        }       
 }

输出：

luffy 19 pomerian
gold 32 german shepherd

在Java中创建对象实例时出错

3 个答案: