Question

我希望views.py中的print（request.method）语句在下面返回POST。我已经看到了request.method是POST的其他代码示例。但是我的代码只输出GET：

TEST1

GET

时，表单正在发送POST数据

经过一番挖掘后，我发现HTTP并不是为了重定向POST数据而设计的：

https://softwareengineering.stackexchange.com/questions/99894/why-doesnt-http-have-post-redirect

但是请我为什么我的代码会重定向此POST数据？我希望我的观点返回“POST”而不是“GET”，因为我没有使用HttpResponseRedirect。想了解为什么会发生这种情况以及我可以做些什么来阻止Django重定向POST数据以获得GET。我错过了什么？

urls.py

from django.urls import path

from . import views

urlpatterns = [
    path('', views.index, name = 'index'),
    path('add_coin/', views.add_coin, name = 'add_coin'),
    path('register/', views.register, name = 'register'),
    path('login/', views.user_login, name='login'),
    path('logout/', views.user_logout, name='logout')
]

forms.py

class PortfolioForm(forms.ModelForm):
    coin = forms.ModelChoiceField(queryset = Coin.objects.all()) 
    amount = forms.IntegerField() 
    trade_price = forms.DecimalField(decimal_places = 2)

    field_order = ['coin', 'amount', 'trade_price']

    class Meta:
        model = Portfolio
        fields = {'coin', 'amount', 'trade_price', 'user'}
        exclude = ['user']

add_coin.html

<form action="{% url index %)" method="post" name="add_coin">
     <table>
          {{ form }}
     </table>
     {% csrf_token %}
     <input type="submit" name="add_coin" formmethod="post" value="Add Coin">
</form>

索引视图（views.py）

def index(request):

    portfolio_list = []
    for coin in Portfolio.objects.filter(user = request.user): #(user = request.user.username):
        portfolio_dict = {}

        coin_str = str(coin.coin)

        portfolio_dict['coin'] = coin_str 
        portfolio_dict['amount'] = coin.amount 
        portfolio_dict['symbol'] = GetCoin(coin_str).symbol 
        portfolio_dict['price'] = GetCoin(coin_str).price 
        portfolio_dict['value'] = GetCoin(coin_str).price * coin.amount 
        portfolio_dict['last_updated'] = GetCoin(coin_str).last_updated 
        portfolio_dict['daily_change'] = GetCoin(coin_str).percent_change_24h
        portfolio_dict['gains'] = coin.trade_price - GetCoin(coin_str).price

        portfolio_list.append(portfolio_dict)
        #print(portfolio_list)  

    def get_top_coins(limit): # display coins if no user is logged in       
        data = requests.get("https://api.coinmarketcap.com/v1/ticker/?limit={}".format(limit)).json()
        y = 0
        coin_list = {
            "image": [],
            "name": [],
            "price": [],
            "symbol": [],
            "market_cap": []
        }

        for x in data:
            coin_list["name"].append(data[y]['name'])
            coin_list["price"].append(data[y]['price_usd'])
            coin_list["symbol"].append(data[y]['symbol'])
            coin_list["market_cap"].append(data[y]['market_cap_usd'])

            y += 1 

        return coin_list

    coin_list = get_top_coins(20)

    for x in coin_list["name"]:
        image = "{}.png".format(x)
        coin_list["image"].append(image)

    context_dict = {'portfolio_list': portfolio_list, 'coin_list': zip(coin_list["image"], coin_list["name"], coin_list["price"], coin_list["market_cap"])}

    return render(request, 'myportfolio/index.html', context = context_dict)

add_coin view（Views.py）：

def add_coin(request):
    print("test 1")
    print(request.method)
    form = PortfolioForm()
    if request.method == "POST":
        form = PortfolioForm(request.POST)
        if form.is_valid():
            print("test 2")
            obj = form.save(commit = False)
            obj.user = request.user
            obj.save()
        else: 
            print(form.errors)

    return render(request, 'myportfolio/add_coin.html', {'form': form})

Answer 1

表单似乎由add_coin视图处理，因此您应该更改表单操作以发布到该表单。

<form action="{% url 'add_coin' %}" method="post" name="add_coin">

然后我希望看到

test1

GET

当您对add_coin视图执行初始GET请求时，

test1

POST

当您使用POST请求提交表单时。

Django：为什么我的表单发送POST数据但返回request.method GET？

1 个答案: