Question

我是Django rest-framework的新手，并试图渲染一个不基于模型的简单JSON视图。我无法弄清楚如何执行此操作，因为所有示例都涉及从Model类渲染JSON。以下是我想要做的简单示例。

class CommentSerializer(serializers.Serializer):
    email = serializers.EmailField()
    content = serializers.CharField(max_length=200)
    created = serializers.DateTimeField()

class Comment(object):
    def __init__(self, email, content, created=None):
        self.email = email
        self.content = content
        self.created = created or datetime.now()

def comment_view(request):
    comment = Comment(email='leila@example.com', content='foo bar')
    serializer = CommentSerializer(comment)
    json = JSONRenderer().render(serializer.data)
    return json

Answer 1

您可以像here一样使用它：

from rest_framework.decorators import api_view
from rest_framework.response import Response


@api_view()
def comment_view(request):
    comment = Comment(email='leila@example.com', content='foo bar')
    serializer = CommentSerializer(comment)
    return Response(serializer.data)

最后别忘了把它放在urls.py：

中

urlpatterns = [
    path('comments/', comment_view, name='comment-view'),
]

Django rest-framework创建一个没有模型的视图

1 个答案: