Question

所以我正在学习如何返回字符串中最常见的字符。我知道怎么做，如果只有一个角色出现最多e.i，＆＃34; a＆＃34;在＆＃34; javascript＆＃34;出现两次，其余字符只出现一次。但是如果字符串是“javascript prototype＆＃39;”，那么最常出现的两个字符是＆＃34; p＆＃34;和＆＃34; t＆＃34;。我正在使用_.invert（）来获取字母最多出现的数字的值，而且我是因为＆＃34; p＆＃34;和＆＃34; t＆＃34;两者都等于3然后我可以归还它们。我期待输出 "p t"

＆＃13;

// Return the character that is most common in a string
// ex. maxCharacter('javascript') == 'a'
// Return multiple characters that are most common in a string
// ex. maxCharacter('javascript prototype') == 'p t'
function maxCharacter(str) {


  const charMap = {};
  let maxNum = 0;
  let maxChar = '';

  str.replace(/\s/gi, '').split('').forEach(function(char){
    if(charMap[char]){
      charMap[char]++;
    } else {
      charMap[char] = 1;
    }
  });
  

  for(let char in charMap){
    if(charMap[char] > maxNum) {
      maxNum = charMap[char];
      maxChar = (_.invert(charMap))[maxNum];
    }
  }
  return maxChar;
}



// Call Function
const output = maxCharacter('javascript prototype');

console.log(output);

＆＃13;

Answer 1

charMap function maxCharacter(str) { const charMap = {}; str.replace(/\s/gi, '').split('').forEach(function(char){ if(charMap[char]){ charMap[char]++; } else { charMap[char] = 1; } }); const max = Math.max(...Object.values(charMap)); return Object.keys(charMap) .filter((c) => charMap[c] === max) .join(' '); } console.log(maxCharacter('javascript')); // a console.log(maxCharacter('javascript prototype')); // p t spreading Object.values()查找Math.max()中的最大数字。然后使用Array.filter()获取具有最大值的键，并使用空格连接它们：

class TimedOutFilter(logging.Filter):
    def filter(self, record):
        if "Error while getting Updates: Timed out" in record.getMessage():
            return False
        return True  # <==== Added this line only

JavaScript |返回字符串

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