Question

这是我的代码：

deckTypes = []
cardType = ["Spade", "Hearts", "Diamonds", "Clubs"]
cardValues = ["Ace", 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, "J", "Q", "K"]
Values = [[1, 11], 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10]
for i in cardType:
    for j in cardValues:
        deckTypes.append(str(j) + " of " + str(i))
deck = dict(zip(deckTypes, Values*4))
z = 0
while z < 5:
    card = random.choice(list(deck))
    handValue = deck[card]
    hand = []
    hand.append(card)
    print(hand)
    z += 1

我正在尝试附加到列表hand，但每次循环结束时它都会重置列表。所以我明白了：

['1 of Spade']
['3 of Spade']
['2 of Clubs']
['K of Hearts']
['4 of Spade']

我怎么能这样做？

['1 of Spade', '3 of Spade', '2 of Clubs', 'K of Hearts', '4 of Spade']

PS：这不是全部代码，但我试图尽可能清楚地理解

Answer 1

您错放了hand的初始化。

使用您当前的代码，hand在每次迭代期间设置为[] ：

z = 0
while z < 5:
    hand = [] # Executed during each iteration
    hand.append(card)
    print(hand)
    z += 1

因此，在每次迭代后，您将得到一个只包含1个元素的列表：

['1 of Spade']
['3 of Spade']
['2 of Clubs']
['K of Hearts']
['4 of Spade']

相反，您应该在循环之前初始化hand ，如下所示：

hand = [] # Executed once, before iterating z = 0 while z < 5: hand.append(card) print(hand) z += 1

现在，您可以看到每次迭代时元素都正确地附加到列表中：

['1 of Spade'] ['1 of Spade', '3 of Spade'] ['1 of Spade', '3 of Spade', '2 of Clubs'] ['1 of Spade', '3 of Spade', '2 of Clubs', 'K of Hearts'] ['1 of Spade', '3 of Spade', '2 of Clubs', 'K of Hearts', '4 of Spade']

退出循环时，hand包含以下列表，如您所愿：

['1 of Spade', '3 of Spade', '2 of Clubs', 'K of Hearts', '4 of Spade']

Answer 2

您的代码输出在此

['3 of Hearts']
['9 of Spade']
['3 of Spade']
['Ace of Diamonds']
['Q of Clubs']

但是当你移动hand = []并打印（hand）out while while循环时

deckTypes = []
cardType = ["Spade", "Hearts", "Diamonds", "Clubs"]
cardValues = ["Ace", 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, "J", "Q", "K"]
Values = [[1, 11], 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10]
for i in cardType:
    for j in cardValues:
        deckTypes.append(str(j) + " of " + str(i))
deck = dict(zip(deckTypes, Values*4))
z = 0
hand = []
while z < 5:
    card = random.choice(list(deck))
    handValue = deck[card]
    hand.append(card)
    z += 1
print(hand)

输出将是：

['7 of Spade', '4 of Clubs', '10 of Clubs', '4 of Spade', '4 of Hearts']

附加到循环中的列表会重置列表

2 个答案: