Question

我有一个代码，如下所示，其中包含uri，并假设uri通过的是http://website.com/accounts/school/index/fr_id/1/stateID/14683/school_name/BANGALORE国际学校（UOL）/

      $uri=$this->uri->uri_to_assoc(4); 

     if(isset($uri['fr_id'])) {  $fr_id=$uri['fr_id'];  }
     else{  $fr_id='';  }
     if(isset($uri['stateID'])) { $stateID=$uri['stateID']; }
     else{  $stateID='';  }
     if(isset($uri['school_name'])) {  $school_name=$uri['school_name'];  }
     else{  $school_name='';  

     echo $fr_id.$stateID.$school_name;exit;
     }

使用此声明，$ uri = $ this-＆gt; uri-＆gt; uri_to_assoc（4）;我无法获取在url中传递的值，需要使用if语句进行检查。任何人都可以帮我解决这个问题吗？当我回显$ fr_id，$ stateID和$ school_name的值时，它们是空的。

Answer 1

希望这会对您有所帮助：

这样做：

$uri = $this->uri->uri_to_assoc(3);
/* OR simply use this */
$uri = $this->uri->uri_to_assoc();  

$fr_id = ! empty($uri['fr_id']) ? $uri['fr_id'] : '';

$stateID = ! empty($uri['stateID']) ? $uri['stateID'] : '';
$school_name = ! empty($uri['school_name']) ? $uri['school_name'] : '';

echo $fr_id.' '.$stateID.' '.$school_name;die;
/*Output - 1 14683 BANGALORE*/

更多信息：https://www.codeigniter.com/userguide3/libraries/uri.html#CI_URI::uri_to_assoc

Answer 2

 public function function_name()
 {
     $uri = $this->uri->uri_to_assoc(); 
     echo $pp=$uri['stateID'];
     echo $school_name=$uri['school_name'];
     echo $fr_id=$uri['fr_id'];
 }

它会正常工作

如何在codeigniter中获取uri的值？

2 个答案: