Question

我有两个实体（employeeTo＆amp; restTo）有一对多的关系在他们之间，我想让员工休息只列出，但是当我加载列表时，每个对象都包含员工对象。

employeeTO

  @OneToMany(mappedBy = "employeeTO",cascade = CascadeType.ALL)
private List<RestTO> RestTOList=new ArrayList<>();

restTO

  @ManyToOne(fetch = FetchType.LAZY)
private EmployeeTO employeeTO;

你可以在下面看到我的代码：

  Session session = HibernateUtil.getSessionFactory().openSession();
Transaction transaction = session.beginTransaction();
Criteria criteria=session.createCriteria(RestTo.class);
criteria.setFetchMode("employeeTO",FetchMode.SELECT);
criteria.createAlias("employeeTO","alians_employee");
Criterion condition1= Restrictions.eq("alians_employee.emID",emid);
criteria.add(condition1);
criteria.add(Restrictions.between("startDate",date1,date2));
List<RestTO> restTOS=criteria.list();
  transaction.commit();
    session.close();

的System.out.println（restTOS.get（0）.getEmployeeTo.getName）;   该指令正在运行并显示员工姓名

我希望无权访问员工对象

我只需加载没有employeeTo值的RestTo对象。我怎么能这样做？感谢。

Answer 1

不要创建别名，它会为您的查询添加内部联接。所以不是这个

Criteria criteria=session.createCriteria(RestTo.class);
criteria.setFetchMode("employeeTO",FetchMode.SELECT);
criteria.createAlias("employeeTO","alians_employee");
Criterion condition1= Restrictions.eq("alians_employee.emID",emid);

使用此

Criteria criteria=session.createCriteria(RestTo.class);
//Default fetchmode is good,no need for that.
//criteria.setFetchMode("employeeTO",FetchMode.SELECT);
//criteria.createAlias("employeeTO","alians_employee");
Criterion condition1= Restrictions.eq("employeeTO.emID",emid);

hibernate条件单个对象加载

1 个答案: