Question

我有一个＆＃34; jvalue＆＃34;包含json数据的变量：

{
    "data": [
        {
            "_id": 123,
            "name": "Name 1"
        },
        {
            "_id": 124,
            "name": "Name 2"
        }  
    ],
    "success": true
}

这是我尝试过的代码：

auto data = jvalue.at(U("data")).at(0);
auto dataObj = data.as_object();

for (auto iterInner = dataObj.cbegin(); iterInner != dataObj.cend(); ++iterInner)
{
    auto &propertyName = iterInner->first;
    auto &propertyValue = iterInner->second;

    std::wcout << "Property: " << propertyName << ", Value: " << propertyValue << std::endl;
}

但它只显示第一组数据：

Property: _id, Value: 123
Property: name, Value: "Name 1"

我知道我在这里遗漏了一些东西，但这个想法不会出现在我脑海中。也许就像双循环一样。

任何人都可以分享这个想法。谢谢。

Answer 1

现在只迭代对象的属性，你也必须迭代数组元素：

auto DataArray = jvalue.at(U("data")).as_array();

for (int i = 0; i< DataArray.size(); i++)
{
    auto data = DataArray[i];
    auto dataObj = data.as_object();

    for (auto iterInner = dataObj.cbegin(); iterInner != dataObj.cend(); ++iterInner)
    {
        auto &propertyName = iterInner->first;
        auto &propertyValue = iterInner->second;

        std::wcout << "Property: " << propertyName << ", Value: " << 
        propertyValue << std::endl;
    }
}

或使用迭代器迭代数组：

auto DataArray = jvalue.at(U("data")).as_array();

for (auto Iter = DataArray.begin(); Iter != DataArray.end(); ++Iter)
{
    auto& data = *Iter;
    auto dataObj = data.as_object();

    for (auto iterInner = dataObj.cbegin(); iterInner != dataObj.cend(); ++iterInner)
    {
        auto &propertyName = iterInner->first;
        auto &propertyValue = iterInner->second;

        std::wcout << "Property: " << propertyName << ", Value: " << 
        propertyValue << std::endl;
    }
}

如何使用cpprest迭代json对象

1 个答案: