在第1行中导出带引号分隔符的文本文件的过程 - Excel

时间:2018-04-30 06:52:44

标签: excel vba csv delimiter

我从微软支持网站LINK

获得了以下代码

问题是它运作得有点好。我只需要#34;"列的第一行(基本上是表头)。预选赛。下面的代码应用了""对所有细胞。

我不知道如何做出这种改变。任何帮助将不胜感激!

非常感谢, OM

Sub QuoteCommaExport()
   Dim DestFile As String
   Dim FileNum As Integer
   Dim ColumnCount As Integer
   Dim RowCount As Integer

DestFile = "C:\Users\Documents\Data\test.txt"

FileNum = FreeFile()


   On Error Resume Next

   Open DestFile For Output As #FileNum

   If Err <> 0 Then
  MsgBox "Cannot open filename " & DestFile
  End
  End If

  On Error GoTo 0

   For RowCount = 1 To Selection.Rows.Count

  For ColumnCount = 1 To Selection.Columns.Count

     Print #FileNum, """" & Selection.Cells(RowCount, _
        ColumnCount).Text & """";

     If ColumnCount = Selection.Columns.Count Then
        Print #FileNum,
     Else
        Print #FileNum, ",";
     End If
  Next ColumnCount

 Next RowCount
Close #FileNum
End Sub

电子表格中选择的数据如下所示:

Date    Close   Open    High    Low
24/04/2008  0.9399  0.9472  0.9484  0.9372
25/04/2008  0.9338  0.9394  0.9423  0.9289
28/04/2008  0.9382  0.9339  0.9405  0.9332

我需要的输出看起来像这样:

"Date","Close","Open","High","Low"
22/06/2015,21,20.698,21.019,20.575
23/06/2015,20.508,20.96,21.052,20.318
24/06/2015,20.679,20.475,20.709,20.287

基于@ DisplayName&#39代码的输出

"Date","Open","High","Low","Close","Volume"
7/08/2015 , 3.84145514 , 4.80521243 , 3.4206597 , 3.76001086 , 164329 
8/08/2015 , 3.78715895 , 3.800733 , 0.97017103 , 1.02256685 , 674188
9/08/2015 , 0.95851228 , 1.19425818 , 0.85406678 , 0.95275825 , 532170 

是否可以删除逗号之间的空格?

2 个答案:

答案 0 :(得分:0)

试试这个:

Sub QuoteCommaExport()
    Dim DestFile As String
    Dim FileNum As Integer
    Dim ColumnCount As Integer
    Dim RowCount As Integer

    DestFile = "C:\Users\Documents\Data\test.txt"
    FileNum = FreeFile()

    On Error Resume Next

    Open DestFile For Output As #FileNum

    If Err <> 0 Then
        MsgBox "Cannot open filename " & DestFile
        Goto CleanExit
    End If

    On Error GoTo 0

    For ColumnCount = 1 To Selection.Columns.Count
        Print #FileNum, """" & Selection.Cells(1, _
           ColumnCount).Text & """";
        If ColumnCount = Selection.Columns.Count Then
           Print #FileNum,
        Else
           Print #FileNum, ",";
        End If
    Next

    For RowCount = 2 To Selection.Rows.Count
        For ColumnCount = 1 To Selection.Columns.Count

            If ColumnCount = Selection.Columns.Count Then
               Print #FileNum, Selection.Cells(RowCount, ColumnCount)
            Else
               Print #FileNum, Selection.Cells(RowCount, ColumnCount); ",";
            End If
        Next ColumnCount

    Next RowCount

CleanExit:
    Close #FileNum
End Sub

答案 1 :(得分:0)

更简单的方法是使用vbCrLf创建一个字符串变量,其中需要启动一个新行,然后在结尾处进行一次打印?我认为这解决了格式化问题:

Sub QuoteCommaExport()
    Dim DestFile As String
    Dim FileNum As Integer
    Dim ColumnCount As Integer
    Dim RowCount As Integer

    DestFile = "C:\Users\Documents\Data\test.txt"
    FileNum = FreeFile()

    On Error Resume Next

    Open DestFile For Output As #FileNum

    If Err <> 0 Then
        MsgBox "Cannot open filename " & DestFile
        Goto CleanExit
    End If

    On Error GoTo 0

    Dim PrintString As String

    For ColumnCount = 1 To Selection.Columns.Count
        PrintString = PrintString & """" & Selection.Cells(1, ColumnCount).Text & """" & IIf(ColumnCount = Selection.Columns.Count, vbCrLf, ",")
    Next
    For RowCount = 2 To Selection.Rows.Count
        For ColumnCount = 1 To Selection.Columns.Count
            PrintString = PrintString & Selection.Cells(RowCount, ColumnCount) & IIf(ColumnCount = Selection.Columns.Count, vbCrLf, ",")
        Next ColumnCount
    Next RowCount
    Print #FileNum, PrintString;

CleanExit:
    Close #FileNum
End Sub