在SFML库c＃

Question

我尝试使用 SFML 库编写代码，当我按一个键时，我更改了一个bool变量。问题是我使用按键操作，我不知道如何实现仅使用1次x键的密钥释放，这就是我正在尝试实现的原因，因为按键会影响多次更改变量的所有时间。

if (Keyboard.IsKeyPressed(Keyboard.Key.A))
{
    values[0] = !values[0];
}
if (Keyboard.IsKeyPressed(Keyboard.Key.S))
{
    values[1] = !values[1];
}
if (Keyboard.IsKeyPressed(Keyboard.Key.D))
{
    values[2] = !values[2];
}

由于

Answer 1

我认为您可以使用Window.KeyPressed和Window.KeyReleased并保存按下并释放的键

private Dictionary<Keyboard.Key, bool> keysArePressed = new Dictionary<Keyboard.Key, bool>
{
   {Keyboard.Key.A, false},
   {Keyboard.Key.S, false},
   {Keyboard.Key.D, false}
};

// Key
Window.KeyPressed += OnKeyPressed;
Window.KeyReleased += OnKeyReleased;

public void OnKeyPressed(object sender, KeyEventArgs e)
{
   if (e.Code == Keyboard.Key.A && !keysArePressed[Keyboard.Key.A])
   {
      Console.WriteLine("A pressed");
      keysArePressed[Keyboard.Key.A] = true;
   }
}

public void OnKeyReleased(object sender, KeyEventArgs e)
{
   if (e.Code == Keyboard.Key.A)
   {
      Console.WriteLine("A released");
      keysArePressed[Keyboard.Key.A] = false;
   }
}