Question

Hello我的简单应用程序始终返回错误消息而不是成功消息。

RegisterActivity.class

   Intent intent=new Intent(getApplicationContext(),LoginActivity.class);

            intent.putExtra ( "user", username.getText().toString() );
            intent.putExtra ( "pass", password.getText().toString() );

            Toast.makeText(getApplicationContext(), Submit, Toast.LENGTH_SHORT).show();
            startActivity(intent);

LoginActivity.class

private EditText username,password;
private Button ok,clear;


//String Array
String LoginSucc = "Login Success";
String LoginFailed= "Login Failed";
String ClearFields = "Text Fields Cleared";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);


    username = findViewById(R.id.txtUsername);
    password = findViewById(R.id.txtPassword);

    ok = findViewById(R.id.Ok);
    clear = findViewById(R.id.Clear);


    ok.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {


            Bundle bb;
            bb=getIntent().getExtras();

            if(username.equals(bb.getString("user"))&& password.equals(bb.getString("pass")))
            {
                Toast.makeText(getApplicationContext(), LoginSucc, Toast.LENGTH_SHORT).show();
            }else {
                Toast.makeText(getApplicationContext(), LoginFailed, Toast.LENGTH_SHORT).show();
            }
        }
    });

即使我输入正确的登录信息，也始终返回LoginFailed消息。

Answer 1

你需要这样做：

ok.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

             String userName = username.getText().toString();
             String passWord = password.getText().toString();
            Bundle bb;
            bb=getIntent().getExtras();

            if(userName.equals(bb.getString("user"))&& passWord.equals(bb.getString("pass")))
            {
                Toast.makeText(getApplicationContext(), LoginSucc, Toast.LENGTH_SHORT).show();
            }else {
                Toast.makeText(getApplicationContext(), LoginFailed, Toast.LENGTH_SHORT).show();
            }
        }
    })

Answer 2

我相信你忘了在第一个活动中创建一个Bundle对象。

RegisterActivity.class

Intent intent = new Intent(getActivity(),LoginActivity.class);
       String username = username.getText().toString();
       String password = password.getText().toString();

       Bundle bb = new Bundle();
       bb.putString("user", username);
       bb.putString("pass", password);

       intent.putExtras(bb);

       startActivity(intent);

LoginActivity.class

 private Bundle bb;
...
    bb = intent.getExtras(); 
    String getUsername = extras.getString("user");
    String getPassword = extras.getString("pass");

始终在简单登录而不是成功消息中返回错误消息

2 个答案: