我正在尝试创建一个sql注入安全的表单,您可以将CSV文件上传到MySQL数据库。我的代码如下所示,它回显了浏览器中csv中的数据,但没有将数据插入数据库。
<?php
require_once("session.php");
require_once("class.user.php");
$user = new USER();
$user_id = $_SESSION['user_session'];
if(isset($_SESSION['user_session']))
{
if (isset($_POST['submit'])) {
$session = $_SESSION['user_session'];
//upload file
if (is_uploaded_file($_FILES['csv']['tmp_name'])) {
echo "<h1>" . "File ". $_FILES['csv']['name'] ." uploaded successfully." . "</h1>";
echo "<h2>Displaying contents:</h2>";
readfile($_FILES['csv']['tmp_name']);
}
//Import uploaded file to Database
$handle = fopen($_FILES['csv']['tmp_name'], "r");
$stmt = $user->runQuery("INSERT INTO main(
first_name,
last_name,
info1,
info2,
info3,
info4,
info5,
info6,
info7,
info8) VALUES(
?,?,?,?,?,?,?,?,?,?)");
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$stmt->bindparam(1, $data[0], PDO::PARAM_STR);
$stmt->bindparam(2, $data[1], PDO::PARAM_STR);
$stmt->bindparam(3, $data[2], PDO::PARAM_STR);
$stmt->bindparam(4, $data[3], PDO::PARAM_STR);
$stmt->bindparam(5, $data[4], PDO::PARAM_STR);
$stmt->bindparam(6, $data[5], PDO::PARAM_STR);
$stmt->bindparam(7, $data[6], PDO::PARAM_STR);
$stmt->bindparam(8, $data[7], PDO::PARAM_STR);
$stmt->bindparam(9, $data[8], PDO::PARAM_STR);
$stmt->bindparam(10, $data[9], PDO::PARAM_STR);
$stmt->execute();
}
fclose($handle);
}
}
?>
答案 0 :(得分:-1)
删除了所有->bindParam
并替换为->execute($data)
。