Question

我正在开展一个个人项目，并坚持提取月份缩写的文字。

示例输入文本的格式为：

text = "apr25, 2016\nblah blah\npow\nmay22, 2017\nasdf rtys\nqwer\njan9, 2018\npoiu\nlkjhj yertt"

我希望输出表格：

[ ("apr25, 2016\nblah blah\npow\n"), ("may22, 2017\nasdf rtys\nqwer\n"), ("jan9, 2018\npoiu\nlkjhj yertt") ]

我尝试了一个简单的正则表达式，但它不正确：

import re

# Greedy version
REGEX_MONTHS_TEXT = re.compile(r'(apr[\w\W]*)|(may[\w\W]*)|(jan[\w\W]*)')
REGEX_MONTHS_TEXT.findall(text)
# output: [('apr25, 2016\nblah blah\npow\nmay22, 2017\nasdf rtys\nqwer\njan9, 2018\npoiu\nlkjhj yertt', '', '')]

# Non-Greedy version
REGEX_MONTHS_TEXT = re.compile(r'(apr[\w\W]*?)|(may[\w\W]*?)|(jan[\w\W]*?)')
REGEX_MONTHS_TEXT.findall(text)
# output: [('apr', '', ''), ('', 'may', ''), ('', '', 'jan')]

你能帮我用python3正则表达式产生所需的输出吗？

或者我是否需要编写自定义python3代码来生成所需的输出？

Answer 1

问题在于我的正则表达式中的月缩写，在匹配月份缩写后停止。

我提到了Python RegEx Stop before a Word并使用了那里提到的驯化贪婪令牌解决方案。

import re

REGEX_MONTHS_TEXT = re.compile(r'(apr|may|jan)((?:(?!apr|may|jan)[\w\W])+)')
text = "apr25, 2016\nblah blah\npow\nmay22, 2017\nasdf rtys\nqwer\njan9, 2018\npoiu\nlkjhj yertt"

arr = REGEX_MONTHS_TEXT.findall(text)
# arr = [ ('apr', '25, 2016\nblah blah\npow\n'),  ('may', '22, 2017\nasdf rtys\nqwer\n'),  ('jan', '9, 2018\npoiu\nlkjhj yertt')]

# The above arr can be combined using list comprehension to form
# list of singleton tuples as expected in the original question
output = [ (x + y,) for (x, y) in arr ]
# output = [('apr25, 2016\nblah blah\npow\n',), ('may22, 2017\nasdf rtys\nqwer\n',), ('jan9, 2018\npoiu\nlkjhj yertt',)]

驯化贪婪令牌的附加资源：Tempered Greedy Token - What is different about placing the dot before the negative lookahead

正则表达式根据月份缩写分割文本并提取以下文本？

1 个答案: