我尝试使用所有数据，但它不起作用，因为我只能得到'size'参数中所述的结果数。这是我的部分代码。
<ReactiveList
componentId="results"
dataField="original_title"
size={1}
showResultStats={true}
pagination={true}
react={{
and: "searchbox"
}}
onAllData={this.onAllData}
/>
onAllData(shops) {
let result = null;
if (shops !== null) {
console.log(shops.length);
result = shops.map((marker) => (
<ListItem>
<Thumbnail square size={80} source={{ uri: 'https://dummyimage.com/80x80/000/fff' }} />
<Body>
<Text>{marker.name}</Text>
<Text note>{marker.dis}</Text>
</Body>
</ListItem>
))
return result;
}
}
答案 0 :(得分：2)
有几种方法可以解决这个问题：
onAllData将提供size道具中指定的结果数量。通常，设置一个非常高的size并不是一个好主意，因为它需要更多的时间来获取和渲染结果。一个很好的替代方法是通过将pagination道具设置为false并在size道具中设置值来使用无限滚动，该值告诉组件到达终点时要获取的结果数量列表。
注意
这个答案使用了用于web的反应搜索（用于演示），但是你可以在reactivesearch-native中使用相同的道具，因为API是相同的。
如果您只对呈现结果感兴趣，则上述方法可以正常工作。但是，如果您希望获取当前查询的所有结果，可以使用Elasticsearch的{{3}} API。您可以使用ReactiveList获取当前查询，然后将其与滚动API一起使用。
为此，您可以使用onQueryChange上的ReactiveList道具：
首先在onQueryChange上指定一个ReactiveList道具，它接收上一个和当前查询作为参数：
onQueryChange={(prev, next) => ...}
每次更改查询时都会调用此函数，这样您就可以编写逻辑来获取当前查询的命中（在next参数中收到）。
滚动API调用以下列格式返回结果：
{
"_scroll_id": "DnF1ZXJ5VGhlbkZldGNoAgAAAAClGlY4FlotbmJJZXA0U09lMlZFMUNyQ3M2M0EAAAAApRpWORZaLW5iSWVwNFNPZTJWRTFDckNzNjNB",
"took": 0,
"timed_out": false,
"_shards": {
"total": 2,
"successful": 2,
"skipped": 0,
"failed": 0
},
"hits": {
"total": 9407,
"max_score": 1,
"hits": [
{
"_index": "good-books-ds",
"_type": "good-books-ds",
"_id": "5676",
"_score": 1,
"_source": {
"authors": "Arthur C. Clarke, Gentry Lee",
"average_rating": 3.76,
"average_rating_rounded": 4,
"books_count": 48,
"id": 5676,
"image": "https://images.gr-assets.com/books/1375814957l/112518.jpg",
"image_medium": "https://images.gr-assets.com/books/1375814957m/112518.jpg",
"isbn": "1857230213",
"language_code": "eng",
"original_publication_year": 1991,
"original_series": "Rama",
"original_title": "The Garden of Rama (Rama, #3)",
"ratings_count": 16389,
"title": "The Garden of Rama (Rama, #3)"
}
},
{
"_index": "good-books-ds",
"_type": "good-books-ds",
"_id": "5681",
"_score": 1,
"_source": {
"authors": "Darren Shan",
"average_rating": 4.22,
"average_rating_rounded": 4,
"books_count": 52,
"id": 5681,
"image": "https://s.gr-assets.com/assets/nophoto/book/111x148-bcc042a9c91a29c1d680899eff700a03.png",
"image_medium": "https://s.gr-assets.com/assets/nophoto/book/111x148-bcc042a9c91a29c1d680899eff700a03.png",
"isbn": "",
"language_code": "",
"original_publication_year": 2003,
"original_series": "Cirque Du Freak",
"original_title": "Killers of the Dawn (Cirque Du Freak, #9)",
"ratings_count": 18194,
"title": "Killers of the Dawn (Cirque Du Freak, #9)"
}
},
{
"_index": "good-books-ds",
"_type": "good-books-ds",
"_id": "5683",
"_score": 1,
"_source": {
"authors": "Laura Joffe Numeroff, Felicia Bond",
"average_rating": 4.16,
"average_rating_rounded": 4,
"books_count": 13,
"id": 5683,
"image": "https://s.gr-assets.com/assets/nophoto/book/111x148-bcc042a9c91a29c1d680899eff700a03.png",
"image_medium": "https://s.gr-assets.com/assets/nophoto/book/111x148-bcc042a9c91a29c1d680899eff700a03.png",
"isbn": "60278684",
"language_code": "",
"original_publication_year": 2000,
"original_series": "",
"original_title": "If You Take a Mouse to the Movies",
"ratings_count": 17938,
"title": "If You Take a Mouse to the Movies"
}
},
{
"_index": "good-books-ds",
"_type": "good-books-ds",
"_id": "5685",
"_score": 1,
"_source": {
"authors": "Orson Scott Card, James Cameron",
"average_rating": 4.06,
"average_rating_rounded": 4,
"books_count": 15,
"id": 5685,
"image": "https://images.gr-assets.com/books/1225165505l/40289.jpg",
"image_medium": "https://images.gr-assets.com/books/1225165505m/40289.jpg",
"isbn": "99690608",
"language_code": "eng",
"original_publication_year": 1989,
"original_series": "",
"original_title": "The Abyss",
"ratings_count": 16318,
"title": "The Abyss"
}
},
{
"_index": "good-books-ds",
"_type": "good-books-ds",
"_id": "5687",
"_score": 1,
"_source": {
"authors": "Katarina Bivald, Alice Menzies",
"average_rating": 3.56,
"average_rating_rounded": 4,
"books_count": 63,
"id": 5687,
"image": "https://images.gr-assets.com/books/1452107441l/25573977.jpg",
"image_medium": "https://images.gr-assets.com/books/1452107441m/25573977.jpg",
"isbn": "149262344X",
"language_code": "eng",
"original_publication_year": 2013,
"original_series": "",
"original_title": "Läsarna i Broken Wheel rekommenderar",
"ratings_count": 14571,
"title": "The Readers of Broken Wheel Recommend"
}
}
]
}
}
作为_scroll_id收到的值可以传递给滚动API以获取下一组结果，依此类推，直到命中数为零。
注意
如果您的群集有大量数据，那么每次查询更改时运行此逻辑以获取所有结果都不是一个好主意。您可以添加条件来限制获取的结果数或将当前查询存储在状态中，并且仅在需要时获取所有结果。
以下是有关如何使用ReactiveList实现此功能的示例。在示例中，我每次查询更改时都会获取结果，但您可以修改它以有条件地获取结果：
在render函数中：
<ReactiveList
...
size={10}
onQueryChange={this.handleQueryChange}
/>
以下是handleQueryChange函数的外观。这将为您提供当前查询的所有结果：
handleQueryChange = async (prev, next) => {
// avoid fetching the results for match_all query since dataset is large
if (next && !next.query.match_all) {
console.log('Fetching all results for query:', next);
// modify the query size here if needed (currently it is 10)
// initial url to obtain scroll id is different
const initialResults = await this.fetchResults(next, url);
// keep scrolling till hits are present
// NOTE: careful if you've a lot of results,
// in that case you might want to add a condition to limit calls to scroll API
const scrollResults = await this.fetchScrollResults({
scroll: "1m",
scroll_id: initialResults._scroll_id
});
// combine the two to get all results
// concat hits from initialResults with hits from scrollResults
const allResults = initialResults.hits.hits.concat(scrollResults);
console.log(`${allResults.length} results found:`, allResults);
}
};
它最初使用两个函数来获取结果，然后使用scroll_id来获取结果。两者的端点不同，您可以在scroll中找到它们。这是第一个fetchResults的样子：
fetchResults = (query, api) => {
return fetch(api, {
method: "POST",
headers: {
"content-type": "application/json",
Authorization: `Basic ${btoa(credentials)}`
},
body: JSON.stringify(query)
})
.then(res => res.json())
.catch(err => console.error(err));
};
fetchScrollResults将使用滚动API获取结果，直到获得的匹配为0。
fetchScrollResults = async query => {
const res = await this.fetchResults(query, scrollUrl);
const { hits } = res.hits;
if (hits.length) {
return [
...hits,
...(await this.fetchScrollResults({
scroll: "1m",
scroll_id: res._scroll_id
}))
];
}
return [];
};
检查demo，结果将显示在控制台中。
答案 1 :(得分：0)
您缺少一个标识唯一组件的键，您还需要将元素包含在函数内部。如果正确调用函数并且数组中有元素，那么这应该可以正常工作。
onAllData(shops) {
let result = null;
if (shops !== null) {
console.log(shops.length);
result = shops.map((marker,index) => { return (
<ListItem key={index}>
<Thumbnail square size={80} source={{ uri: 'https://dummyimage.com/80x80/000/fff' }} />
<Body>
<Text>{marker.name}</Text>
<Text note>{marker.dis}</Text>
</Body>
</ListItem>
)})
return result;
}