Question

我已经在我的php脚本中声明了一个名为test_input的函数，它在另一个脚本中运行得非常好。

显示错误

致命错误：未捕获错误：在C：\ xampp \ htdocs \ submitdata \ cwisubmit.php中调用未定义函数test_input（）：25堆栈跟踪：＃0 {main}在C：\ xampp \ htdocs \ submitdata \中引发第25行的cwisubmit.php

我的PHP脚本是：

<?php 
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "test";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);

// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

echo "Database Connected SUCCESSFULLY";

if($_SERVER["REQUEST_METHOD"]=="POST") {
    // Variables initialization
    $fname=$lname=$dob=$phone=$email=$postcode=$staddress=$city=$lan=$lcwi=$ptype=$mhtype="";

    // Retrieving the data from the form
    $fname=test_input(mysqli_real_escape_string($conn,$_POST['fname']));
    $lname=test_input(mysqli_real_escape_string($conn,$_POST['lname']));
    $dob=test_input(mysqli_real_escape_string($conn,$_POST['dob']));
    $phone=test_input(mysqli_real_escape_string($conn,$_POST['phone']));
    $email=test_input(mysqli_real_escape_string($conn,$_POST['email']));
    $postcode=test_input(mysqli_real_escape_string($conn,$_POST['postcode']));
    $staddress=test_input(mysqli_real_escape_string($conn,$_POST['staddress']));
    $city=test_input(mysqli_real_escape_string($conn,$_POST['city']));
    $lan=test_input(mysqli_real_escape_string($conn,$_POST['lan']));
    $lcwi=test_input(mysqli_real_escape_string($conn,$_POST['lcwi']));
    $ptype=test_input(mysqli_real_escape_string($conn,$_POST['ptype']));
    $mhtype=test_input(mysqli_real_escape_string($conn,$_POST['mhtype']));

  function test_input($data) {
      $data=trim($data);
      $data=stripslashes($data);
      return $data;
  }

  //sql insert
  $sql="INSERT INTO cwi(fname, lname, dob, phone, email, postcode, staddress, city, lan, lcwi, ptype, mhtype) VALUES('$fname','$lname','$dob','$phone','$email','$postcode','$staddress','$city','$lan','$lcwi','$ptype','$mhtype')";

  if($conn->query($sql)===TRUE){
      echo "<center>RECORDS UPDATED SUCCESSFULLY</center>";
  }else{
      echo "Error: ".$sql."<br>".$conn->error;
  }
}

$conn->close();
?>

请检查此代码我的代码是否有错误或为何返回此错误

Answer 1

可以在定义PHP函数之前调用它，因为PHP首先解析文件然后执行它。但这是扭曲。

条件语句（if else）中包含的函数将不被解析。它仅在PHP解释if
后才可用

所以，你必须将你的功能移到IF块之外，如

if(condition){
//your code
}
//Your function
  function test_input($data){
      $data=trim($data);
      $data=stripslashes($data);
      return $data;
  }

Answer 2

对代码进行了更改尝试此操作。它应该工作正常。

<?php 


$servername = "localhost";
$username = "root";
$password = "";
$dbname = "test";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
    if ($conn->connect_error) 
   {
        die("Connection failed: " . $conn->connect_error);
    } 



echo "Database Connected SUCCESSFULLY";

    if($_SERVER["REQUEST_METHOD"]=="POST"){
  //Variables initaition
  $fname=$lname=$dob=$phone=$email=$postcode=$staddress=$city=$lan=$lcwi=$ptype=$mhtype="";

  //Retrieving the data from the form
  $fname=test_input(mysqli_real_escape_string($conn,$_POST['fname']));
  $lname=test_input(mysqli_real_escape_string($conn,$_POST['lname']));
  $dob=test_input(mysqli_real_escape_string($conn,$_POST['dob']));
  $phone=test_input(mysqli_real_escape_string($conn,$_POST['phone']));
  $email=test_input(mysqli_real_escape_string($conn,$_POST['email']));
  $postcode=test_input(mysqli_real_escape_string($conn,$_POST['postcode']));
  $staddress=test_input(mysqli_real_escape_string($conn,$_POST['staddress']));
  $city=test_input(mysqli_real_escape_string($conn,$_POST['city']));
  $lan=test_input(mysqli_real_escape_string($conn,$_POST['lan']));
  $lcwi=test_input(mysqli_real_escape_string($conn,$_POST['lcwi']));
  $ptype=test_input(mysqli_real_escape_string($conn,$_POST['ptype']));
  $mhtype=test_input(mysqli_real_escape_string($conn,$_POST['mhtype']));


  //sql insert
  $sql="INSERT INTO cwi(fname, lname, dob, phone, email, postcode, staddress, city, lan, lcwi, ptype, mhtype) VALUES('$fname','$lname','$dob','$phone','$email','$postcode','$staddress','$city','$lan','$lcwi','$ptype','$mhtype')";

  if($conn->query($sql)===TRUE){
      echo "<center>RECORDS UPDATED SUCCESSFULLY</center>";
  }else{
      echo "Error: ".$sql."<br>".$conn->error;
  }
        }

  $conn->close();

  function test_input($data)
 {
      $data=trim($data);
      $data=stripslashes($data);
      return $data;
  }
?>

Answer 3

在

之外定义你的test_input（）函数

if($_SERVER["REQUEST_METHOD"]=="POST"){

和你的代码

 if($_SERVER["REQUEST_METHOD"]=="POST"){

似乎错过了“}”

在php函数中显示错误

3 个答案: