我有一个对象数组。这些对象具有名为std::string s;
std::cin >> s;
return s;
的属性。如果时间相同,我想将这些对象分组到同一个数组中。
time
我想将上述数据格式化为:
{ "00:00" :
[{"id":1, time: "00:05",
{"id":1, time: "00:15",
{"id":1, time: "00:20",
{"id":2, time: "00:05",
{"id":3, time: "00:05",
{"id":4, time: "00:35 }]
}
关于如何实现这一目标的任何建议?
答案 0 :(得分:3)
你可以尝试使用Array的reduce()
,如下所示:
var obj = { "00:00" :
[{"id":1, time: "00:05"},
{"id":1, time: "00:15"},
{"id":1, time: "00:20"},
{"id":2, time: "00:05"},
{"id":3, time: "00:05"},
{"id":4, time: "00:35" }]
}
var res = obj['00:00'].reduce(function(a, c){
a[c.time] = a[c.time] || [];
a[c.time].push(c);
return a;
}, {});
console.log(res);
.as-console-wrapper { top: 0; }
答案 1 :(得分:3)
您可以使用reduce
汇总您的对象,并使用Object.values
将对象转换为数组
let obj={"00:00" :[{"id":1,time:"00:05"},{"id":1,time:"00:15"},{"id":1,time:"00:20"},{"id":2,time:"00:05"},{"id":3,time:"00:05"},{"id":4,time:"00:35"}],"02:00" :[{"id":1,time:"00:05"},{"id":1,time:"00:15"},{"id":1,time:"00:20"},{"id":2,time:"00:05"},{"id":3,time:"00:05"},{"id":4,time:"00:35"}]}
var result = Object.entries(obj).reduce((c, v) => {
c[v[0]] = Object.values(v[1].reduce((a, o) => {
a[o.time] = a[o.time] || [];
a[o.time].push(o);
return a;
}, {}));
return c;
}, {});
console.log(result);
答案 2 :(得分:2)
使用.reduce
将所有匹配的对象放入由时间索引的对象内的数组中,然后从对象中提取值:
const input = { "00:00" :
[{"id":1, time: "00:05"},
{"id":1, time: "00:15"},
{"id":1, time: "00:20"},
{"id":2, time: "00:05"},
{"id":3, time: "00:05"},
{"id":4, time: "00:35" }]
};
const outputObj = input['00:00'].reduce((accum, { id, time }) => {
if (!accum[time]) accum[time] = [];
accum[time].push({ id, time });
return accum;
}, {});
const outputArr = Object.values(outputObj);
console.log(outputArr);
您还可以将其扩展为应用于input
数组的多个属性:
const input = { "00:00" :
[{"id":1, time: "00:05"},
{"id":1, time: "00:15"},
{"id":1, time: "00:20"},
{"id":2, time: "00:05"},
{"id":3, time: "00:05"},
{"id":4, time: "00:35" }],
"01:00" :
[{"id":1, time: "01:05"},
{"id":1, time: "01:15"},
{"id":1, time: "01:20"},
{"id":2, time: "01:05"},
{"id":3, time: "01:05"},
{"id":4, time: "01:35" }],
};
function transformInputArrToGroupedArr(inputArr) {
const outputObj = inputArr.reduce((accum, { id, time }) => {
if (!accum[time]) accum[time] = [];
accum[time].push({ id, time });
return accum;
}, {});
return Object.values(outputObj);
}
const transformedInput = Object.entries(input).reduce((accum, [ key, arr ]) => {
accum[key] = transformInputArrToGroupedArr(arr);
return accum;
}, {});
console.log(transformedInput);