Hibernate - 从Annotations到XML配置文件

时间:2011-02-15 17:18:18

标签: java hibernate hibernate-annotations

我使用Hibernate Annotations来映射表,但我想转移到xml映射文件(* hbm.xml),我遇到了一些麻烦。我有4个表(用户,汽车,租赁,user_car)和3个类(用户,汽车,租赁)

用户

@Entity
@Table(name = "USERS")
@SuppressWarnings("serial")
public class User implements Serializable {

  private Long id;
  private List<Car> cars;

  @Id
  @GeneratedValue
  @Column(name = "ID")
  public Long getId() {
      return id;
  }
  @OneToMany(cascade = CascadeType.ALL)
  @JoinTable(name = "USER_CAR", joinColumns = { @JoinColumn(name = "CAR_ID") },   inverseJoinColumns = { @JoinColumn(name = "USER_ID", referencedColumnName = "ID") })
  public List<Car> getCars() {
      return cars;
  }
 ...
}

汽车

@Entity
@Table(name = "CARS")
@SuppressWarnings("serial")
public class Car implements Serializable {

  private Long id;
  private User owner;

  @Id
  @GeneratedValue
  @Column(name = "ID")
  public Long getId() {
      return id;
  }
  @OneToOne(cascade = CascadeType.ALL)
  @JoinTable(name = "USER_CAR", joinColumns = { @JoinColumn(name = "CAR_ID", referencedColumnName = "ID") }, inverseJoinColumns = { @JoinColumn(name = "USER_ID") })
  public User getOwner() {
      return owner;
  }
...
}

租赁

@Entity
@Table(name = "RENTALS")
@SuppressWarnings("serial")
public class Rental implements Serializable {

  private Long id;
  private Car car;
  private User user;
  private Date date;

  @Id
  @GeneratedValue
  @Column(name = "ID")
  public Long getId() {
      return id;
  }
  @ManyToOne
  @JoinColumn(name = "CAR_ID")
  public Car getCar() {
      return car;
  }
  @ManyToOne
  @JoinColumn(name = "USER_ID")
  public User getUser() {
      return user;
  }
  @Column(name = "RENT_DATE", nullable=false)
  @Temporal(TemporalType.DATE)
  public Date getDate() {
      return date;
  }
...
}

Eclipse生成了映射文件,并且我做了一些改进

汽车

<hibernate-mapping>
<class name="com.bontade.mvc.models.Car" table="CARS">
    <id name="id" type="java.lang.Long">
        <column name="ID" />
        <generator class="assigned" />
    </id>
    <many-to-one name="owner" class="com.bontade.mvc.models.User" fetch="join">
        <column name="USER_CAR" />
    </many-to-one>
</class>
</hibernate-mapping>

用户

<hibernate-mapping>
<class name="com.bontade.mvc.models.User" table="USERS">
    <id name="id" type="java.lang.Long">
        <column name="ID" />
        <generator class="assigned" />
    </id>
    <property name="name" not-null="true" length="100" type="java.lang.String">
        <column name="NAME" />
    </property>
    <list name="cars" inverse="false" table="CAR" lazy="true">
        <key>
            <column name="ID" />
        </key>
        <list-index></list-index>
        <one-to-many class="com.bontade.mvc.models.Car" />
    </list>
</class>
</hibernate-mapping>

租赁

<hibernate-mapping>
<class name="com.bontade.mvc.models.Rental" table="RENTALS">
    <id name="id" type="java.lang.Long">
        <column name="ID" />
        <generator class="assigned" />
    </id>
    <many-to-one name="car" class="com.bontade.mvc.models.Car" fetch="join">
        <column name="CAR_ID" />
    </many-to-one>
    <many-to-one name="user" class="com.bontade.mvc.models.User" fetch="join">
        <column name="USER_ID" />
    </many-to-one>
    <property name="date" type="java.util.Date">
        <column name="RENT_DATE" />
    </property>
</class>
</hibernate-mapping>

但是,我不知道如何声明和连接“代理”表USER_CAR。

2 个答案:

答案 0 :(得分:2)

这样的话,请参阅8.5. Bidirectional associations with join tables

<class name="com.bontade.mvc.models.Car" table="CARS">
    ...
    <join table="USER_CAR" 
        inverse="true" 
        optional="true">
        <key column="CAR_ID"/>
        <many-to-one name="owner"
            column="USER_ID"
            not-null="true"/>
    </join>
</class>

<class name="com.bontade.mvc.models.User" table="USERS">
    ...
    <list name="cars" inverse="false" table="USER_CAR" lazy="true">
        <key>
            <column name="CAR_ID" />
        </key>
        <many-to-many column = "USER_ID" unique = "true" 
            class="com.bontade.mvc.models.Car" />
    </list>
</class>

答案 1 :(得分:1)

这样的内容应该放在用户定义中。

  <join table="USER_CAR" optional="true">
    <key column="user_id" unique="true"/>
    <many-to-one name="car" column="car_id" not-null="true"/>
  </join>