Question

制作24小时制。 24小时是钟表将从零小时计数到23小时。但钟面只有小时的AM编号或任何时候显示的小时的PM编号。 AM编号从0到11. PM从12到23 我需要使用drawNum代码，我无法使其工作，这是我到目前为止的代码......

float x[], y[]; 
float diam;  
color c[];
int n; //number of balls 

void setup()
{
  size (500, 500);
  colorMode(HSB);
  background(0);
  frameRate(1);
  x = new float [n];
  y = new float [n];
}

void draw()
{
  float h, m, s; 
  float radius; 
  float cx, cy;


  float clockface; 
  float hoursRadius, minutesRadius, hoursTick, secondsRadius, minutesTick;

  radius = min(height/2.0, width/2.0); 
  cx = width/2.0;
  cy = height/2.0;  

  clockface = radius * 0.9;
  hoursRadius = radius * 0.5;
  minutesRadius = radius * 0.65;
  secondsRadius = radius * 0.72;
   hoursTick = radius * 0.04;
   minutesTick = hoursTick * 0.5;

  // get time 
  s = second(); 
  m = minute(); 
  h = hour()%12 + m/60.0; 

  //draw clock face 
  fill(40);
  noStroke();
  ellipseMode(RADIUS);
  ellipse(cx, cy, clockface, clockface); 

  //
  drawHand(cx, cy, s*6.0, secondsRadius, 2); 
  drawHand(cx, cy, m*6.0, minutesRadius, 3); 
  drawHand(cx, cy, h*30.0, hoursRadius, 5); 


for ( int i=0; i<60; i++) {
   if (i%5==0) {
     drawNum(cx, cy, i*6, secondsRadius, 10, 0);
   } else {
     drawNum(cx, cy, i*6, secondsRadius, 5, 23);
    }
  }

  // draw the ticks
  for ( int i=0; i<60; i++) {
    if (i%5==0) {
      drawTick(cx, cy, i*6, secondsRadius, 10);
    } else {
      drawTick(cx, cy, i*6, secondsRadius, 5);
    }
  }
}
void drawTick( float x, float y, 
  float angle, float len, 
  float weight) {
  fill(angleToColor(angle));
  noStroke();
  rectMode(CENTER);
  rect(x + cos(radians(angle-90))*len, 
    y + sin(radians(angle-90))*len, 
    weight, weight) ;
}
void drawHand( float x, float y, 
  float angle, float len, 
  float weight) {

  strokeWeight(weight); 
  stroke(angleToColor(angle)); 
  line(x, y, 
    x + cos(radians(angle-90))*len, 
    y + sin(radians(angle-90))*len);
}

color angleToColor(float angle) { 
  return color(map(angle, 0, 360, 0, 255), 255, 255);
}

void drawNum(float x,float y, 
  float angle, float len, 
  float tsize, int num) {
float i;  
     textSize(36);
  fill(0);
  noStroke();
  for (num = 0; num < 12; num++) {
     int hoursNum = (x + cos(radians(angle-90))*len, 
    y + sin(radians(angle-90))*len, 
    num, num)) ;;


 }
  }

Answer 1

您需要将数字转换为字符串（文本）以显示它。这是通过函数str(arg)完成的，它返回类型String的值。参数arg可以是int，float，char，byte或boolean类型。

绘制文字的功能是text( s, x, y )，其中s是要显示的字符串，x和y是位置。

修改

hour()函数返回24小时制的小时数，从0-23而不是1-24开始计算。右键单击Processing窗口中的函数，然后选择“Find in Reference”以查看详细信息。代码hour()%12将小时值取模12，这意味着当值达到12时，它将循环回零，而值12-23则报告为0-11。

将数字添加到模拟时钟处理

1 个答案: