Question

| email                           |
+---------------------------------+
| abcd@gmail.com                  |
| bdef@gmail.com abdfgr@yahoo.com |
+---------------------------------+

我尝试了下面的内容，它正在为第一行工作

substr(email,instr(email,'@',1,1))

但是对于同一个小区的第二行，我们有2个域ID。现在，如何检索输出如下

gmail.com
gmail.com
yahoo.com

Answer 1

例如：

public ActionResult DisplaySearchResults(int[] SelectedGenres) //selected genres from multiselect list
{
    List<Movie> SelectedMovies = new List<Movie>();
    SelectedMovies = db.Movies.ToList();
    var query = from r in db.Movies.Include("Genres")
                select r;

    if (SelectedGenres == null || SelectedGenres.Count() == 0) 
    {
        ViewBag.SelectedGenre = "No genre was selected";
    }
    else
    {
        foreach (int GenreID in SelectedGenres)
        {
            //need to query where there's at least one genre, not all
            //EX.Western and Horror selected should return movies that have either western or horror as a genre, not both.
            query = query.Where(r => r.Genres.Any(x => x.GenreID == GenreID));
        }
    }

    SelectedMovies = query.ToList();
    return View("Index", SelectedMovies);
 }

Answer 2

您可以使用REGEXP_SUBSTR，例如：

SELECT REGEXP_SUBSTR ('jlora@outlook.com', '(\@).*') from DUAL

结果：@ outlook.com

Answer 3

您可以尝试以下内容。我假设你的桌子上还有一个或多个主键列也有电子邮件列：

email

See SQL Fiddle here（忽略架构！）。

现在上面的查询将获得所有结果，包括重复项，因此，如果you@yahoo.com you@gmail.com you@gmail.com列中的值如下所示：gmail.com那么SELECT将为该主键返回两次值。只需将SELECT DISTINCT替换为{{1}}即可解决该问题（如果您想绕过它）。

Oracle sql正则表达式按模式拆分字符串

3 个答案: