我正在尝试将python函数添加到我的代码中,但是当我这样做时,我得到一个UnboundLocalError:
追踪(最近一次呼叫最后一次):
文件“/Users/name/Documents/project.py”,第44行,in 逻辑(coinType,3.56,bagWeight,356,0.01)
文件“/Users/name/Documents/project.py”,第14行,逻辑 valueAddedCoins + = value UnboundLocalError:赋值前引用的局部变量'valueAddedCoins'
def logic(coin_txt, w1, wBag, cWeight, vCoin):
diff = abs(wBag - cWeight)
if diff == 0:
print("Bag ok")
return
coins = diff / w1
value = coins * vCoin
if wBag < cWeight:
valueAddedCoins += value
print(int(coins), coin_txt, " coins missing")
print(diff, "grams too little")
else:
valueRemovedCoins += value
print(int(coins), coin_txt, " coins too many")
print(diff, " grams too many")
valueAddedCoins = 0
valueRemovedCoins = 0
numBagsChecked = 0
continueChecking = True;
while continueChecking:
#asking information about the coins and deducing wether or not the weight is correct
bagWeight = float(input("Weight of bag of coins (no unit): "))
coinType = input("Type of coins in bag: 1 pence or 2 pence?")
numBagsChecked += 1
if coinType == "1 pence":
logic(coinType, 3.56, bagWeight, 356, 0.01)
elif type_of_coin == "2 pence":
logic(coinType, 7.12, bagWeight, 712, 0.02)
check = input("Another bag? (Y/N): ")
if check == "N":
continueChecking = False
为什么我会收到UnboundLocalError?
答案 0 :(得分:0)
您可以添加
global valueAddedCoins
定义后的功能
答案 1 :(得分:0)
变量valueAddedCoins不在函数logic
的范围内
请参阅主题
为了能够修改它,你必须在函数内声明它为global
:
def logic(coin_txt, w1, wBag, cWeight, vCoin):
global valueAddedCoins
valueAddedCoins += 1
但这通常被认为是非常糟糕的做法,因为这样的代码通常很难调试(因为很难找到修改这些全局变量的地方,这些错误来自哪里)
替代方法是将其传入并返回其修改后的值,如下所示:
def increment_int(valueAddedCoins):
return valueAddedCoins += 1
valueAddedCoins = increment_int(valueAddedCoins)
通过这种方式,您将始终知道修改了您的变量等等。