Question

我有一个清单，例如

[True, True, True, True, False, False, True, False, True, True, False]

我想知道 True 是连续的最小计数，因此在这种情况下为1。

或者在以下列表中，它是2，

[True, True, False, True, True, False, False, False, False, True, True, True]

感谢您的帮助！

Answer 1

这是我的（幼稚）解决方案：

GREEN=$(tput setaf 2)
RED=$(tput setaf 1)
NC=$(tput sgr0)

输出：

list_1 = [True, True, True, True, False, False, True, False, True, True, False]
list_2 = [True, True, False, True, True, False, False, False, False, True, True, True] 
list_3 = [False, False, False]
list_4 = [True, True, True]
list_5 = [False, False, False, True, True]

def min_successive_val_count(list_of_vals):
  list_of_runs = []
  counter = 0
  for val in list_of_vals:
    if val:
      counter+=1
    else:
      if counter != 0:
        list_of_runs.append(counter)
      counter = 0
  if list_of_runs:
    return min(list_of_runs)
  elif counter == len(list_of_vals):
    return counter
  elif list_of_vals[-1]:
    return counter
  else:
    return "No True's in your list"

print(min_successive_val_count(list_1))
print(min_successive_val_count(list_2))
print(min_successive_val_count(list_3))
print(min_successive_val_count(list_4))
print(min_successive_val_count(list_5))

祝你好运（希望我的最后一次编辑;）

Answer 2

来自Python: A program to find the LENGTH of the longest run in a given list?，但最多 - ＆gt;分钟。

Entry

Answer 3

让我们在遍历此列表时使用字典记录我们的真实计数器。

list = [True, True, False, True, True, False, False, False, False, True, True, True]

currentCounter = 0

record = []

def getMin (list):   
    for x in list:
        if x:
            currentCounter[0] = currentCounter[0]+1
        else:
            record.append(currentCounter)
            currentCounter = 0
    return secondSmallest(record)

#we need to get the second smallet number because always the smallest is equal 0
def secondSmallest(numbers):
    m1, m2 = float('inf'), float('inf')
    for x in numbers:
        if x <= m1:
            m1, m2 = x, m1
        elif x < m2:
            m2 = x
    return m2

获取最小连续值计数（如果有）

3 个答案: