Question

我是Python的初学者，我的目标是编写一个驻留在git服务器上的预接收挂钩。

如果任何消息未通过格式检查，钩子应该检查提交消息的格式并拒绝推送。

我认为我对此进行了简单的提交模式比较，如下所示：

commit_list = ['test1', 'test2', 'test3', 'test4']
patterns = ['test1','test2']

matched = set(commit_list).intersection(patterns) # find matches

for match in matched:
    commit_list[:] = (commit for commit in commit_list if commit != match) # remove matches from commit_list

commit_list_length = len(commit_list)

if commit_list_length == 0: # all commits matched so the list is empty
    print('all commit messages match the format')
else:
    print('%s of the commit messages don\'t match the format' % commit_list_length)
    print(commit_list)

如何修改此代码段以包含regexp，例如：re.match(pattern,commit)？

因此，当第二行更改为例如：

时，它仍然有效

patterns = ['test[0-9]{1,5}','test: ']

Answer 1

如果您想更改代码以包含re.match()，可以尝试此操作。

import re
commit_list = ['test1', 'test2', 'test3', 'test4']
patterns = ['test1','test2']
regx=re.compile(r'{}'.format("|".join(patterns)))
commit_unmatched=[commit for commit in commit_list if not regx.match(commit)]
print(commit_unmatched)

Answer 2

我认为我找到了一个有效的解决方案，但几乎可以肯定，它不是最短或最有效的解决方案：

commit_list = ['test1', 'test234', 'testA', 'test:a', 'test: a']
patterns = ['test[0-9]{1,5}','test: ']

cloned_list = list(commit_list) # copy list of commits

for item in commit_list:
    for pattern in patterns:
        if re.match(pattern,item):
            cloned_list.remove(item) # work on the copy and discard matched
        elif not re.match(pattern,item):
            continue # exhaust all possibilities

cloned_list_length = len(cloned_list)

if cloned_list_length == 0: # all commits matched so the list is empty
    print('all commit messages match the format')
else:
    print('%s of the commit messages don\'t match the criteria' % cloned_list_length)
    print(cloned_list) # only print unmatched

仍然愿意尝试更好的建议！

Python 3中列表交集中的模式匹配

2 个答案: