Question

我正在尝试使用下面的代码使用改装2发送图像，但我收到的图像已损坏，无法使用Windows照片查看器打开。你有两个截图，第一个是我被解析为字符串的内容，第二个是我尝试打开图像时得到的消息。我已经尝试了不同的选项来读取已发送图像的流，但没有一个工作。一个是wcf中的代码我使用的另外两个选项是注释的代码，但它们都不起作用。希望有人能帮助我。

        @Multipart
        @POST("PostImageJSON")
        Call<String> PostImage(@Part MultipartBody.Part report_image);



                    MediaType imageType = MediaType.parse("image/*");
                    File file = new File(ImagePath+"/savedReportPhoto.jpg");

                    if(file.exists()) {
                        RequestBody requestBodyImage = RequestBody.create(imageType, file);
                        MultipartBody.Part image = MultipartBody.Part.createFormData("uploadedImage", file.getName(), requestBodyImage);
                        Call<String> callSendImage = api.PostImage(image);


                        progress.setTitle("Procesim");
                        progress.setMessage("Duke procesuar..");
                        progress.setCancelable(false); // disable dismiss by tapping outside of the dialog
                        progress.show();

                        callSendImage.enqueue(new Callback<String>() {
                            @Override
                            public void onResponse(Call<String> call, Response<String> response) {
                                if (response.isSuccessful()) {
                                    String responseimg = response.body();

                                    progress.dismiss();
                                } else {
                                    Toast.makeText(getApplicationContext(), "Something went wrong with the request to the server !", Toast.LENGTH_SHORT).show();
                                    progress.dismiss();
                                }
                            }

                            @Override
                            public void onFailure(Call<String> call, Throwable t) {
                                progress.dismiss();
                                Toast.makeText(getApplicationContext(), t.getMessage(), Toast.LENGTH_SHORT).show();
                            }
                        });

                    }

            [OperationContract]
            [WebInvoke(Method = "POST", UriTemplate = "/PostImageJSON", BodyStyle = WebMessageBodyStyle.Bare, RequestFormat = WebMessageFormat.Json,
            ResponseFormat = WebMessageFormat.Json)]
            String PostImage(Stream postedImage);

        public String PostImage(Stream postedImage)
        {
  //Here i parse the stream as string for testing purposes
            StreamReader reader = new StreamReader(postedImage);
            string res = reader.ReadToEnd();

            using (StreamWriter writer = new StreamWriter("F:\\image.txt", true))
            {
                writer.WriteLine(res);
            }


    //First option i have tried
            //do
            //{
            //    bytesRead = postedImage.Read(buffer, 0, buffer.Length);
            //    totalBytesRead += bytesRead;

            //    ms.Write(buffer, 0, bytesRead);
            //} while (bytesRead > 0);

            //using (FileStream fs = File.OpenWrite("F:\\postedImage.png"))
            //{
            //    ms.WriteTo(fs);
            //    fs.Close();
            //    ms.Close();
            //}

            //Second option i have tried
            byte[] buffer = new byte[19127];
            postedImage.Read(buffer, 0, 19127);
            FileStream f = new FileStream("F:\\savedReportPhoto.jpg", FileMode.OpenOrCreate);
            f.Write(buffer, 0, buffer.Length);
            f.Close();
            postedImage.Close();
            return "Recieved the image on server";

  //Third option i have tried
            //FileStream f = new FileStream("F:\\savedReportPhoto.jpg", FileMode.OpenOrCreate);
            //postedImage.CopyTo(f);
            //f.Close();
            //postedImage.Close();
            //return "Recieved the image on server";

          }

The image content i recieve as string

When i try to open the photo on windows photoviewer

Answer 1

好的我在经过一周的努力后找到了解决方案，解决方案是不将图像与其他数据分开，而是将其编码为base64字符串并将其与对象一起发送，然后在服务器中对其进行解码做你想做的事。

这是改造界面中的方法：

 @POST("PostBanderolDataJSON")
    Call<ReportPostData> PostData(@Header("Authorization") String serviceToken,@Body ReportPostData reportdata);

在这里我发送数据以及编码图像：

            ReportPostData rpd = new ReportPostData();

            rpd.setBanderolnr(banderoNr);
            rpd.setPharmacy(pharmacy);
            rpd.setPlace(place);

            ByteArrayOutputStream baos = new ByteArrayOutputStream();
            Bitmap bmp = Common.loadImageFromStorage(ImagePath);
            if(bmp!=null) {
                bmp.compress(Bitmap.CompressFormat.PNG, 100, baos);
                byte[] imageBytes = baos.toByteArray();
                String encodedImage = android.util.Base64.encodeToString(imageBytes, Base64.DEFAULT);
                rpd.setImageFile(encodedImage);
            }

然后将图像添加到对象中，如上所示：

rpd.setImageFile(encodedImage);

并将对象加入，并像往常一样通过改造发送。

希望有人找到这个有用的

通过改装到WCF的图像发送被破坏

1 个答案: