我有一个查询,我想查找其他表中的值作为参考,但不会弄乱我当前的查询结果。我想我必须使用外部左连接,但不知道如何将其与我当前的查询合并。
我当前的查询与此类似:
SELECT a.primary_key,
a.phase,
b.project_number,
c.LENGTH,
d.color
FROM TableA a,
TableB b,
TableC c,
TableD d
WHERE c.primary_key = a.PROJECT_ID
AND b.primary_key = a.PROJECT_ID
AND b.primary_key = d.project_ID
AND (c.date IS NULL OR c.number IS NULL)
AND d.color IN ('black','red','blue')
ORDER BY 1
现在,这给了我一张包含50个结果的表格。 ' TableContacts'具有我的b.project_number的查找值。所以说我的50个结果表,其中只有10个有b.project_number,我需要来自' TableContacts'的查找值。也显示在我的结果中,但我不希望这会影响我的结果并将其降低到10,我仍然需要我原来的50个结果,只需要附加信息。帮助
答案 0 :(得分:1)
只需将CONTACTS
表添加到您的联接中:
SELECT a.primary_key,
a.phase,
b.project_number,
c.LENGTH,
d.color,
ct.lookup_value --<< this is from the CONTACTS table
FROM TableA a
JOIN TableB b ON b.primary_key = a.PROJECT_ID
JOIN TableC c ON c.primary_key = a.PROJECT_ID
JOIN TableD d ON b.primary_key = d.project_ID
LEFT JOIN contacts ct ON ct.some_column = b.project_Number --<< this is the outer join to the CONTACTS table
WHERE (c.date IS NULL OR c.number IS NULL)
AND d.color IN ('black','red','blue')
ORDER BY 1
当您对表名和列名进行模糊处理时,很难猜测CONTACTS
表上的连接条件应该是多么接近。
答案 1 :(得分:0)
你可以使用这种方法:
创建一个包含当前查询结果的表格:
create table t1 as
SELECT a.primary_key,
a.phase,
b.project_number,
c.LENGTH_col,
d.color
FROM a,b,c,d
WHERE c.primary_key = a.PROJECT_ID
AND b.primary_key = a.PROJECT_ID
AND b.primary_key = d.project_ID
AND (c.date_col IS NULL OR c.number_col IS NULL)
AND d.color IN ('black','red','blue')
ORDER BY 1;
使用联合来获得所需的结果:
select t1.primary_key, t1.phase, t1.project_number, t1.length_col, t1.color, TableContacts.lookup_column
from t1, TableContacts
where t1.project_number = TableContacts.project_number
UNION
select t1.primary_key, t1.phase, t1.project_number, t1.length_col, t1.color, null
from t1 where t1.project_number is null;
通过创建虚拟数据进行说明:
select * from a;
PRIMARY_KEY | PROJECT_ID | PHASE
1 100 Phase-1
2 200 Phase-2
3 300 Phase-3
4 400 Phase-4
5 500 Phase-5
select * from b;
PRIMARY_KEY | PROJECT_NUMBER
100 null
200 2000
300 3000
400 null
500 5000
select * from c;
PRIMARY_KEY | NUMBER_COL | LENGTH_COL | DATE_COL
100 null 99 null
200 null 99 null
300 null 99 null
400 null 99 null
500 null 99 null
select * from d;
PROJECT_ID | COLOR
100 black
200 red
300 blue
400 black
500 yellow
select * from TableContacts;
PROJECT_NUMBER | LOOKUP_COLUMN
1000 l-1000
2000 l-2000
3000 l-3000
4000 l-4000
5000 l-5000
有问题的现有查询会返回:
SELECT a.primary_key,
a.phase,
b.project_number,
c.LENGTH_col,
d.color
FROM a,b,c,d
WHERE c.primary_key = a.PROJECT_ID
AND b.primary_key = a.PROJECT_ID
AND b.primary_key = d.project_ID
AND (c.date_col IS NULL OR c.number_col IS NULL)
AND d.color IN ('black','red','blue')
ORDER BY 1;
PRIMARY_KEY | PHASE | PROJECT_NUMBER | LENGTH_COL | COLOR
1 Phase-1 null 99 black
2 Phase-2 2000 99 red
3 Phase-3 3000 99 blue
4 Phase-4 null 99 black
目标是填充lookup_column
project_number
不为空的地方。运行在答案开头提供的联合查询:
select t1.primary_key, t1.phase, t1.project_number, t1.length_col, t1.color, TableContacts.lookup_column
from t1, TableContacts
where t1.project_number = TableContacts.project_number
UNION
select t1.primary_key, t1.phase, t1.project_number, t1.length_col, t1.color, null
from t1 where t1.project_number is null;
PRIMARY_KEY | PHASE | PROJECT_NUMBER | LENGTH_COL | COLOR | LOOKUP_COLUMN
1 Phase-1 null 99 black null
2 Phase-2 2000 99 red l-2000
3 Phase-3 3000 99 blue l-3000
4 Phase-4 null 99 black null