Question

我对泛型和类型约束感到困惑，我会直截了当地说。

我有一个BaseQueryResult类

public abstract class BaseQueryResult<T>
{
    public int Count => Models != null && Models.Any() ? Models.Count : 0;

    public Exception Exception { get; set; }

    public bool HasException => Exception != null;

    public bool IsSuccess => Exception == null;

    public bool NotFound { get; set; }

    public string ContinuationToken { get; set; }

    public IList<T> Models { get; set; }
}

继承自上述

的子类

public class TransportListingQueryResult : BaseQueryResult<TransportListingQueryModel>
{
    public TransportListingQueryResult(IList<TransportListingQueryModel> models, string continuationToken)
    {
        Models = models;
        ContinuationToken = continuationToken;
        NotFound = false;
    }

    public TransportListingQueryResult(Exception exception)
    {
        NotFound = false;
        Exception = exception;
    }

    public TransportListingQueryResult(bool notFound, Exception exception)
    {
        NotFound = notFound;
        Exception = exception;
    }

    public static TransportListingQueryResult NotFoundResult(Exception exception)
    {
        return new TransportListingQueryResult(true, exception);
    }
}

我正在使用的扩展方法

public static class TransportListingQueryResultExtension
{
    public static IActionResult ToActionResult<T>(this T result, ControllerBase controller, int limit, string routeName, object values, HttpStatusCode successStatusCode = HttpStatusCode.OK)
        where T : BaseQueryResult<T>
    {
        if (result.NotFound)
        {
            return controller.NotFound();
        }

        if (!result.IsSuccess)
        {
            if (result.HasException)
            {
                throw result.Exception;
            }

            return controller.BadRequest(new ErrorResponse { Messages = new[] { ErrorMessages.InternalServer } });
        }

        var uri = controller.Url.Link(routeName, values);
        var response = new HyperMediaResponse<T>(
            new LinkItem(uri),
            new PageItem(limit, result.ContinuationToken, result.Count),
            result.Models);

        switch (successStatusCode)
        {
            case HttpStatusCode.Created:
                return controller.Created(string.Empty, response);
            case HttpStatusCode.OK:
            default:
                return controller.Ok(response);
        }
    }
}

最后我的控制器中的动作

public async Task<IActionResult> Create([FromBody]CreateListingModel createListing)
    {
        var result = await _transportListingStore.CreateNewAsync(createListing);
        return result.ToActionResult<TransportListingQueryResult>(this, 1, Constants.RouteNames.CreateListing, null, HttpStatusCode.Created);
    }

我在行动中遇到错误 return result.ToActionResult （这个， 1， Constants.RouteNames.CreateListing，空值， HttpStatusCode.Created ）;

错误是：

类型＆＃39; TransportListings.API.Application.Response.TransportListingQueryResult＆＃39;不能用作类型参数＆＃39; T＆＃39;在泛型类型或方法＆＃39; TransportListingQueryResultExtension.ToActionResult（T，ControllerBase，int，string，object，HttpStatusCode）＆＃39;。来自＆＃39; TransportListings.API.Application.Response.TransportListingQueryResult＆＃39;没有隐式引用转换。到＆＃39; TransportListings.API.Application.Response.BaseQueryResult＆＃39;

我很困惑，因为我的子类继承了BaseQueryResult，但错误告诉我没有隐式引用转换。我不太确定我的代码有什么问题，以及为什么它会给我错误。

任何帮助将不胜感激。提前谢谢。

Answer 1

问题是你的约束无法满足：

public static IActionResult ToActionResult<T>(this T result, /* snip */)
    where T : BaseQueryResult<T>

你真正想要的是：

public static IActionResult ToActionResult<T, U>(this T result, /* snip */)
    where T : BaseQueryResult<U>

并称之为：

return result.ToActionResult<TransportListingQueryResult, TransportListingQueryModel>(
    this, /* snip */);

如何在此方案中正确使用泛型和类型约束？

1 个答案: