Question

我正在开发一个C＃discord bot，我已经成功让机器人响应以＆＃34; c开头的短语！＆＃34;并使用正确的命令进行响应，但是如果提到机器人，我希望机器人使用GIF进行回复。如果有人可以帮助解释为什么这不起作用以及如何解决它会很好。这是我现在的代码：

    private async Task HandleCommandAsync(SocketMessage arg)
    {
        var message = arg as SocketUserMessage;

        if (message is null || message.Author.IsBot) return;

        int argPos = 0;

        if (message.HasStringPrefix("", ref argPos))
        {
            var context = new SocketCommandContext(_client, message);

            var result = await _commands.ExecuteAsync(context, argPos, _services);

            if (!result.IsSuccess)
                Console.WriteLine(result.ErrorReason);
        }

        if (message.HasMentionPrefix(_client.CurrentUser, ref argPos))
        {
            var embed = new EmbedBuilder();
            embed.WithImageUrl("https://cdn.discordapp.com/attachments/138522037181349888/438774275546152960/Ping_Discordapp_GIF-downsized_large.gif");

            await ReplyAsync("", false, embed.Build());
        }

Answer 1

最好创建一个Modules文件夹，并在单独的.cs文件中添加命令。为此，您需要在启动_client之后但在调用LoginAsync之前添加此行代码。

_client.MessageReceived += HandleCommandAsync;
await _commands.AddModulesAsync(Assembly.GetEntryAssembly());

然后，创建一个单独的新类。您的命令可以接受SocketGuildUser作为参数。在聊天类型！help @name中调用命令：

public class Help : ModuleBase<SocketCommandContext>
{
    [Command("help")]
    public async Task HelpAsync(SocketGuildUser user)
    {
        await ReplyAsync($"{user.Mention} needs a lot of help!");
    }
}

你的HandleCommandAsync应如下所示：

    private async Task HandleCommandAsync(SocketMessage arg)
    {
        var message = arg as SocketUserMessage;

        if (message == null || message.Author.IsBot) return;            

        int argPos = 0;
        if (message.HasStringPrefix("!", ref argPos) ||
            message.HasMentionPrefix(_client.CurrentUser, ref argPos))
        {
            var context = new SocketCommandContext(_client, message);

            var result = await _commands.ExecuteAsync(context, argPos, _services);

            if (!result.IsSuccess)
            {
                Console.WriteLine(result.ErrorReason);
            }
        }
    }

Answer 2

我同意Solarcloud所说的关于分离模块的内容，但这是您必须修改代码的全部内容：

private async Task HandleCommandAsync(SocketMessage arg)
{
    var message = arg as SocketUserMessage;

    if (message is null || message.Author.IsBot) return;

    int argPos = 0;

    if (message.HasStringPrefix("", ref argPos))
    {
        var context = new SocketCommandContext(_client, message);

        var result = await _commands.ExecuteAsync(context, argPos, _services);

        if (!result.IsSuccess)
            Console.WriteLine(result.ErrorReason);
    }

    if (message.content.contains(_client.CurrentUser.Mention.Replace("!", "")))
    {
        var embed = new EmbedBuilder();
        embed.WithImageUrl("https://cdn.discordapp.com/attachments/138522037181349888/438774275546152960/Ping_Discordapp_GIF-downsized_large.gif");

        await ReplyAsync("", false, embed.Build());
    }

替换以防万一您的机器人ID返回@<!123456789>，摆脱它可以正常工作。

我怎样才能让我的Discord C＃响应提及？

2 个答案: