Question

函数2使用函数1返回，而函数3使用两个返回，如何干净利落？函数3只返回未定义的值right nom。

以下是我的3个功能。

功能1

$scope.nombreCompetencesATraiter = function(){
var nbr = 0;
        notesService.getNotesByCollaborateurId($scope.idCollaborateurSelectionne).then(function(data){
            $scope.myNotes = data;
            angular.forEach($scope.myNotes, function(valueNote, keyNote) {
                if ((valueNote.status === "EN_ATTENTE_DE_VALIDATION") || (valueNote.status === "EN_ATTENTE_DE_SUPPRESSION")){
                    nbr++;
                }
            })
            console.log(nbr);
            return nbr;
        })
    }

功能2

$scope.affinerConfigBoutonsCompetences = function() {
        nbCompetenceATraiter = $scope.nombreCompetencesATraiter();
        if (nbCompetenceATraiter == 0){
            $scope.radioModelFilterToutesLesCompetences = true;
            $scope.radioModelFilterCompetencesAValider = false;
        }
        else{
            $scope.radioModelFilterCompetencesAValider = true;
            $scope.radioModelFilterToutesLesCompetences = false;
        }
    }

功能3

$scope.affinerConfigBoutonsCompetencesThen = function(){
        $q.all([$scope.nombreCompetencesATraiter(), $scope.affinerConfigBoutonsCompetences()]).then(function(value) {
            console.log(value[0]);
            console.log(value[1]);
        })
    }

非常感谢。

Answer 1

功能1 在调用noteService

之前缺少return语句

$scope.nombreCompetencesATraiter = function() {
var nbr = 0;
  return notesService.getNotesByCollaborateurId($scope.idCollaborateurSelectionne)
    .then(function(data) {
      $scope.myNotes = data;
      angular.forEach($scope.myNotes, function(valueNote, keyNote) {
        if ((valueNote.status === "EN_ATTENTE_DE_VALIDATION") || (valueNote.status === "EN_ATTENTE_DE_SUPPRESSION")) {
          nbr++;
        }
      })
      console.log(nbr);
      return nbr;
  })
}

功能2

$scope.affinerConfigBoutonsCompetences = function() {
  return $scope.nombreCompetencesATraiter().then(function (value) {
    nbCompetenceATraiter = value;
    if (nbCompetenceATraiter == 0) {
      $scope.radioModelFilterToutesLesCompetences = true;
      $scope.radioModelFilterCompetencesAValider = false;
    } else {
      $scope.radioModelFilterCompetencesAValider = true;
      $scope.radioModelFilterToutesLesCompetences = false;
    }
    return nbCompetenceATraiter // value you want to return
  });
}

功能3

$scope.affinerConfigBoutonsCompetencesThen = function(){
    $q.all([$scope.nombreCompetencesATraiter(), $scope.affinerConfigBoutonsCompetences()]).then(function(value) {
        console.log(value[0]);
        console.log(value[1]);
    })
}

现在让它如何运作！

Answer 2

你有一些Luillyfe提到的错误，一般来说这是解决这种依赖的最简洁方法。

var f1 = () => new Promise( resolve => resolve('value1'));
var f2 = ( value1 ) => new Promise( resolve => resolve('value2'));
var f3 = ( value1, value2 ) => new Promise( resolve => resolve('done'));

f1()
    .then( value1 => Promise.all([ value1, f2( value1 ) ]) )
    .then( ([ value1, value2 ]) => f3( value1, value2 ))

将Promise.all与非Promise值一起使用非常方便，它会直接将它们传递给then。

如何在javascript angularJS中处理嵌套的promises

2 个答案: