Question

我正在尝试动态根据属性的值将对象数组拆分成组。

以下是输入的示例：

`input = [
    {"name": "john", "location": "first"},
    {"name": "steve", "location": "first"},
    {"name": "paul", "location": "another"},
    {"name": "tony", "location": "random"},
    {"name": "ant", "location": "random"}
]`

和所需的输出：

`solution(input, location) = [
    first:   [{"name": "john", "location": "first"},
              {"name": "steve", "location": "first"}],
    another: [{"name": "paul", "location": "another"}],
    random:  [{"name": "tony", "location": "random"},
              {"name": "ant", "location": "random"}]
]`

我不知道位置可以是的值（但我知道密钥名称）

我试图避免使用任何外部库，（这是一个有角度的5项目）但如果它变得非常容易，那么我就不会反对它。

提前致谢

Answer 1

使用Array#reduce：

＆＃13;

const input = [{"name":"john","location":"first"},{"name":"steve","location":"first"},{"name":"paul","location":"another"},{"name":"tony","location":"random"},{"name":"ant","location":"random"}];

const group = input.reduce((acc, item) => {
  if (!acc[item.location]) {
    acc[item.location] = [];
  }

  acc[item.location].push(item);
  return acc;
}, {})

console.log(group);

＆＃13;

修改1

如果您想迭代结果，可以使用for...of循环Object.entries，如下所示：

for (let [location, persons] of Object.entries(group)) {
  console.log(location, persons);
  // do your stuff here
}

根据属性的值动态地将对象数组拆分为组

1 个答案: