CakePHP 3.x更新多行

时间:2018-04-26 14:12:02

标签: cakephp-3.0

我有一个表AssetsAssignations,有数百行。在某些情况下,用户需要选中带有复选框的多行,并更改" status"对于他们所有人。

在我的控制器中,我有这个功能

public function editMultiple()
{
    $assetStatuses = $this->AssetsAssignations->AssetStatuses->find('list');
    $this->paginate = [
        'contain' => ['Assets', 'AssetStatuses', 'Clients', 'Rooms'],
        'sortWhitelist' => [
            'Assets.model_number',
            'Assets.serial_number',
            'AssetStatuses.name',
            'Clients.last_name',
            'Rooms.name',
            ]
    ];

    $assetsAssignations = $this->request->data;

    $assetsAssignations_ids = array();

    foreach($assetsAssignations as $a){
        $assetsAssignations_ids[$a['id']] = $a['id'];
        $this->AssetsAssignations->updateAll(

            array('AssetAssignation.id' => $assetsAssignations_ids)
        );
        $this->Session->setFlash(__('Statsus is updated for the selcted entries!'));
    }            
    debug($assetsAssignations);

    $query = $this->AssetsAssignations->find()
        ->contain(['Assets', 'AssetStatuses', 'Clients', 'Rooms']);
    $filter = $this->Filter->prg($query);
    $assetsAssignations = $this->paginate($filter, ['maxLimit' => 10000, 'limit' => 10000]);        

    $this->set(compact('assetsAssignations', 'assetStatuses'));
    $this->set('_serialize', ['assetsAssignations']);
}

在我的edit_multiple.ctp中,我使用javascript来过滤数据。我把这段代码:

<table class="hoverTable dataTable">
        <thead>
                <tr>
                    <th>Select</th><th>Model Number</th><th>Serial Number</th><th>Room</th><th>Client</th><th>Status</th>
                </tr>
        </thead>
        </thead>
                    <?php foreach ($assetsAssignations as $assetsAssignation): ?>
                    <tr>
                        <td><input name="data[AssetsAssignations][id][]" value="<?= $assetsAssignation->id ?>" id="AssetsAssignationsId1" type="checkbox"></td>
                        <td><?= $assetsAssignation->has('asset') ? $assetsAssignation->asset->model_number : '' ?></td>
                        <td><?= $assetsAssignation->has('asset') ? $assetsAssignation->asset->serial_number : '' ?></td>
                        <td><?= $assetsAssignation->has('room') ? $assetsAssignation->room->name : '' ?></td>
                        <td><?= $assetsAssignation->has('client') ? $assetsAssignation->client->last_name . ', ' . $assetsAssignation->client->first_name: '' ?></td>
                        <td><?= $assetsAssignation->has('asset_status') ? $assetsAssignation->asset_status->name : '' ?></td>
                    </tr>
                    <?php endforeach; ?>
    </table>
    <legend><?= __('') ?></legend>
    </div>
        <?= $this->Form->create($assetsAssignation) ?>
    <fieldset>
        <div class="row">
            <div class="col-xs-3"><?= $this->Form->input('asset_status_id', ['options' => $assetStatuses, 'empty' => true, 'label' => __('Change Status To')]) ?></div>
        </div>
    </fieldset>
    <?= $this->Form->button(__('Submit')) ?>
    <?= $this->Form->end() ?>

当我调试结果时,检查3个条目,我得到了这个:

[
'data' => [
    'AssetsAssignations' => [
        'id' => [
            (int) 0 => '411',
            (int) 1 => '413',
            (int) 2 => '415'
        ]
    ]
],
'asset_status_id' => '3'

我的问题是:如何将选定的行ID传递给&#34;提交&#34;选中复选框后按钮?

提前致谢。

2 个答案:

答案 0 :(得分:1)

我认为您想要做的就像

if($this->request->is('post')
{
    $ids = $this->request->data('data.AssetsAssignations.id');
    $asset_status_id = $this->request->data('asset_status_id');

    $this->AssetsAssignations->updateAll(
        ['asset_status_id ' => $asset_status_id ]
        ['id IN' => $ids]
    );

}

答案 1 :(得分:1)

根据@Arilia的建议,这对我有用。在我的控制器,功能,我把它:

    $this->request->data;
    $data = $this->request->data;
    debug($data);

    if($this->request->is(['patch', 'post', 'put'])) 
    {
        $ids = $this->request->data('data.AssetsAssignations.id');
        $asset_status_id = $this->request->data('asset_status_id');

        $this->AssetsAssignations->updateAll(
            ['asset_status_id ' => $asset_status_id ],
            ['id IN' => $ids]
        );

    }

在我看来,我把它放在了:

<td><input type="checkbox" name="data[AssetsAssignations][id][]" value="<?= $assetsAssignation->id ?>" id="ApplicationId1" ></td>