Question

我在CoGroupFunction中使用广播变量时遇到错误。如果注释df['timestamp'].diff() # .select(1 < x < 10)，则错误消失。你知道如何解决这个问题吗？是与变量定义或初始化相关的错误吗？

appProvider.value()

我收到此错误

public class UsageJobDS implements Serializable{
  private static final Logger log = org.apache.log4j.LogManager.getLogger("myLogger");

  Broadcast<Provider> appProvider;

  void init(){
    // init broadcast variable
    ....
  }
  public static void main(String[] args) {
    UsageJobDS ujb = new UsageJobDS();
    ujb.init();
    ujb.run();
  }

  void run(){
    KeyValueGroupedDataset<Long, Row> charges = usageCharges.groupByKey(x -> x.getLong(x.fieldIndex("si__subscription_id")), Encoders.LONG());

    Dataset<ProcessEdr> cogg = edrs.cogroup(charges, rateEDRs, Encoders.bean(ProcessEdr.class));

    log.warn("Count cogg " + cogg.count());
  }

  CoGroupFunction<Long, EDR2, Row, ProcessEdr> rateEDRs = (subscription_id, edrsIter, chargesIter) -> {
        Logger log = org.apache.log4j.LogManager.getLogger("myLogger");
        log.warn("inside rateEDRs function");

        while (edrsIter.hasNext()) {
            appProvider.value(); // HERE
        }
        return results.iterator();
    };

}

Answer 1

实际上，如果将cogroup函数定义更改为以下代码，则它可以正常工作。但是，错误原因仍然未知。

        Dataset<ProcessEdr> cogg = edrs.cogroup(charges, (subscription_id, edrsIter, chargesIter) -> {
            ArrayList<ProcessEdr> results = new ArrayList<>();

            System.out.println("App Provider name" + appProvider.value().getIssuer_name());

            return results.iterator();
        }, Encoders.bean(ProcessEdr.class));

在apache spark中使用广播变量

1 个答案: