使用子选择值进行PostgreSQL计算

时间:2018-04-26 13:22:50

标签: postgresql join subquery alias postgresql-9.3

使用PostgreSQL 9.3,我试图根据电子邮件表中的子选择结果计算一些值。 以下是我想要做的事情,这当然会产生SQL错误,因为您无法在SELECT中引用别名值:

SELECT 
    email.key,
    email.col1,
    email.col2,
    (SELECT count(sent.subscriber_key) FROM sent WHERE sent.email_id = email.key) AS sent_count,
    (SELECT count(bounce.subscriber_key) FROM bounce WHERE bounce.email_id = email.key) AS bounce_count,
    ((bounce_count / sent_count) * 100) as bounce_pct
FROM
    email
ORDER BY 
    email.key

我尝试将子选择逻辑移到WITH子句中:

WITH
    sent_tmp AS (SELECT count(sent.subscriber_key) as count FROM sent INNER JOIN email ON sent.send_id = email.key),
    bounce_tmp AS (SELECT count(bounce.subscriber_key) as count FROM bounce INNER JOIN email ON bounce.send_id = email.key)
SELECT 
    email.key,
    email.col1,
    email.col2,
    email.sent_date,
    sent_tmp.count,
    bounce_tmp.count,
    ((bounce_tmp.count / sent_tmp.count) * 100) as bounce_pct
FROM
    email,
    sent_tmp,
    bounce_tmp
ORDER BY 
    email.key

...我尝试将其移入FROM子句:

SELECT 
    email.key,
    email.col1,
    email.col2,
    sent_count,
    bounce_count,
    ((bounce_count / sent_count) * 100) as bounce_pct
FROM
    email,
    (SELECT count(sent.subscriber_key) FROM sent INNER JOIN email ON sent.send_id = email.key) AS sent_count,
    (SELECT count(bounce.subscriber_key) FROM bounce INNER JOIN email ON bounce.send_id = email.key) AS bounce_count
ORDER BY 
    email.key

... 但无论哪种方式都会产生无效的已发送和跳出数。 (每封电子邮件的数字都是相同的。)我可能不了解PostgreSQL查询语法的执行顺序,或者没有为电子邮件表中的每一行结果评估子选择。

如果有人能够指出我正确的方向,让我知道什么是可能的,我们将不胜感激!将子选择逻辑移入WITH或FROM时,我是否遗漏了一些关键语法?我需要使用命名变量吗?功能

我意识到可以添加另一个子选择,它会重新计算发送和跳出表中的subscriber_key列,但我试图避免重新计算以提高效率。 (可读性,就此而言。)

1 个答案:

答案 0 :(得分:0)

简单的解决方案是计算外部查询中的值:

SELECT key, col1, col2, sent_count, bounce_count,
       100.0 * bounce_count / sent_count AS bounce_pct
FROM (SELECT key, col1, col2,
            (SELECT count(sent.subscriber_key)
             FROM sent
             WHERE sent.email_id = email.key
            ) AS sent_count,
            (SELECT count(bounce.subscriber_key)
             FROM bounce
             WHERE bounce.email_id = email.key
            ) AS bounce_count
      FROM email
     ) q
ORDER BY key;