Question

我有一个包含Name和TypeId的包含列表，我想为它创建一个包含某些TypeId的给定项目的排除列表。但是，如果名称根本没有出现在列表中，那么它就不会被排除在任何类型之外。

如何使用linq执行此操作？

       List<NameTypeFilter> includeList = new List<NameTypeFilter>();
        includeList.Add(new NameTypeFilter
        {
            Name = "N1",
            Type = "T1"
        });


        MyItem myItem1 = new MyItem();
        myItem1.Type = "T1";

        MyItem myItem2 = new MyItem();
        myItem1.Type = "T2";

        MyItem myItem3 = new MyItem();
        myItem1.Type = "T3";

        //  excludelist for myItem1 should contain nothing
        //  excludelist for myItem2 should contain N1
        //  excludelist for myItem3 should contain N1

        includeList.Add(new NameTypeFilter
        {
            Name = "N2",
            Type = "T2"
        });

        //  excludelist for myItem1 should contain N2
        //  excludelist for myItem2 should contain N1
        //  excludelist for myItem3 should contain N1,N2

Answer 1

如果您共享代码示例，将有助于更详细地了解您的查询但是根据我的假设，如果你使用TakeWhile或Linq的SkipWhile添加Linq条件，它可能会帮助你获得欲望结果

Answer 2

includeList.Where(y => !includeList.Any(z => z.Type == currentItemType && y.Name == z.Name))

我认为这样做

Linq包含/排除逻辑

2 个答案: