Question

问题很明显，正如我在标题中所提到的，任何帮助都会受到赞赏......

顺便说一句，我的服务是在Jboss 4.2.2GA上运行的，而我正在使用MyEclipse7.5 此外，这是我以前尝试过但不适合我的事情;

@Stateless
@WebService(name = "BaseService", targetNamespace = "http://base.ws.listingapi.gg.com")
@SOAPBinding(style = SOAPBinding.Style.RPC)
@WebContext(contextRoot = "/listingapi/ws")
public abstract class BaseService {
    ..

    MessageContext mctx = webServiceContext.getMessageContext();

    webServiceContext.getUserPrincipal(); //WITH THIS ONE I could get the username but of course not password..
    System.out.println(mctx.get("password"));

    Map http_headers = (Map) mctx.get(MessageContext.HTTP_REQUEST_HEADERS);
    List userList = (List) http_headers.get("Username");
    List passList = (List) http_headers.get("Password");

[解决] 我找到了解决方案，就在这里;

@Context
protected HttpServletRequest request;

或者

@Context
protected WebServiceContext context;

...

    request.getUserPrincipal().getName(); 
    //OR
    context.getUserPrincipal().getName();
    //will return the username used to getting logged in

Answer 1

[求助]我找到了解决方案，就在这里;

@Context
protected HttpServletRequest request;

或者

@Context
protected WebServiceContext context;

...

request.getUserPrincipal().getName(); 
//OR
context.getUserPrincipal().getName();
//will return the username used to getting logged in

具有基本身份验证的Ejb jax-rpc Web服务如何获取请求的用户名和密码

1 个答案: