Question

这是我的auth.php：

'guards' => [
    'web' => [
        'driver' => 'session',
        'provider' => 'users',
    ],

    'admin' => [
        'driver' => 'session',
        'provider' => 'admins',
    ],

],

现在，如果user和admin都在同一个浏览器中登录，我该如何检查哪个警卫发出了请求？

请注意，无论是谁提出请求，Auth::guard('admin')->check()和Auth::check()都会返回true。

Answer 1

我假设您想知道哪个警卫auth()->user()所指-哪个auth()->guard()可以访问

不幸的是，没有一个现成的功能可以实际获得守卫的 name 。您可以使用auth()->guard()->getName()，但返回防护的会话标识符（即login_guardname_sha1hash），但是如果需要，可以将其提取：

$guard = auth()->guard(); // Retrieve the guard
$sessionName = $guard->getName(); // Retrieve the session name for the guard
// The following extracts the name of the guard by disposing of the first
// and last sections delimited by "_"
$parts = explode("_", $sessionName);
unset($parts[count($parts)-1]);
unset($parts[0]);
$guardName = implode("_",$parts);

Answer 2

获取应用程序中定义的所有防护措施，并找到当前用户登录时使用的防护措施。

#!/bin/bash

# semicolon removed
count=10

# numerical version of 'for'
for (( i = 1; i <= count; i++ ))
do
    # here we use printf to get a number with at least 2 digits
    printf -v num %02d $i

    # touch is not needed, because the following line
    # will create and update timestamps too

    # create and touch file. Text is an UUID.
    uuidgen > "IN-USS-NABT-A-TATNov-$num.txt"
done

我怎样才能找到哪个“守卫”在Laravel中提出了当前的要求？

2 个答案: