Question

作为一名新手，我试图将swagger-core与我的其他api整合在一起 - ＆gt; https://github.com/swagger-api/swagger-core/wiki/Swagger-Core-Jersey-2.X-Project-Setup-1.5

面对BeanConfig的setScan功能的一些问题所以降级反射包，可以从下面的maven文件中看到：

    <dependency>
         <groupId>io.swagger</groupId>
         <artifactId>swagger-jaxrs</artifactId>
         <version>1.5.18</version>
         <exclusions>
             <exclusion>
                 <groupId>org.reflections</groupId>
                 <artifactId>reflections</artifactId>
             </exclusion>
         </exclusions>
    </dependency>
    <dependency>
        <groupId>org.reflections</groupId>
        <artifactId>reflections</artifactId>
        <version>0.9.10</version>
    </dependency>
    <dependency>
         <groupId>org.webjars</groupId>
         <artifactId>swagger-ui</artifactId>
         <version>3.13.6</version>
         <scope>runtime</scope>
    </dependency>

这是应用程序启动方法：

 public void start() throws Exception {
       BeanConfig beanConfig = new BeanConfig();
       beanConfig.setVersion("2.0");
       beanConfig.setSchemes(new String[]{"http"});
       beanConfig.setHost("0.0.0.0:8082");
       beanConfig.setBasePath("/test");
       beanConfig.setResourcePackage("io.confluent.kafkarest.resources");
       beanConfig.setScan(true);
       beanConfig.setPrettyPrint("true");
       if (server == null) {
         createServer();
       }
    server.start();
  }

通过这个我能够在根路径生成swagger.json。现在，我想把这个json提供给swagger ui，所以我在maven pom.xml中增加了依赖性，如上所示。并修改了如下代码：

      public void start() throws Exception {
           BeanConfig beanConfig = new BeanConfig();
           beanConfig.setVersion("2.0");
           beanConfig.setSchemes(new String[]{"http"});
           beanConfig.setHost("0.0.0.0:8082");
           beanConfig.setBasePath("/test");
           beanConfig.setResourcePackage("io.confluent.kafkarest.resources");
           beanConfig.setScan(true);
           beanConfig.setPrettyPrint("true");
           if (server == null) {
             createServer();
           }
        server.setHandler(buildSwaggerUI()); //--> added this method call.
        server.start();
      }

      public static ContextHandler buildSwaggerUI() throws Exception {
        ResourceHandler rh = new ResourceHandler();
        rh.setResourceBase(KafkaRestApplication.class.getClassLoader()
            .getResource("META-INF/resources/webjars/swagger-ui/3.13.6")
            .toURI().toString());
        ContextHandler context = new ContextHandler();
        context.setContextPath("/swagger");
        context.setHandler(rh);
        return context;
      }

在此之后，我能够获得相当默认的swagger ui，但现在swagger.json已经消失了。我不再是swagger.json了。我试着关注这个博客： https://danielflower.github.io/2016/04/01/Swagger-with-embedded-jetty-without-magic.html

我真的很想让swagger ui与swagger json spec一起工作。我觉得我错过了一些傻事？请帮忙。

Answer 1

我按照this链接开始工作。我的工作代码看起来像这样：

      public void start() throws Exception {
           BeanConfig beanConfig = new BeanConfig();
           beanConfig.setVersion("2.0");
           beanConfig.setSchemes(new String[]{"http"});
           beanConfig.setHost("0.0.0.0:8082");
           beanConfig.setBasePath("/test");
           beanConfig.setResourcePackage("io.confluent.kafkarest.resources");
           beanConfig.setScan(true);
           beanConfig.setPrettyPrint("true");
           if (server == null) {
             createServer();
           }
        final HandlerList handlers = new HandlerList();
        handlers.addHandler(buildSwaggerUI());
        handlers.addHandler(buildContext());
        server.setHandler(handlers);
        server.start();
      }

      private static ContextHandler buildContext() {
        ResourceConfig resourceConfig = new ResourceConfig().packages(WS_PACKAGE, "io.swagger.jaxrs.listing");
        ServletContainer servletContainer = new ServletContainer(resourceConfig);
        ServletHolder eBrowser = new ServletHolder(servletContainer);
        ServletContextHandler eContext = new ServletContextHandler(ServletContextHandler.SESSIONS);
        eContext.setContextPath("/");
        eContext.addServlet(eBrowser, "/*");

        return eContext;
      }

      public static ContextHandler buildSwaggerUI() throws Exception {
        ResourceHandler rh = new ResourceHandler();
        rh.setResourceBase(KafkaRestApplication.class.getClassLoader()
            .getResource("META-INF/resources/webjars/swagger-ui/3.13.6")
            .toURI().toString());
        ContextHandler context = new ContextHandler();
        context.setContextPath("/swagger");
        context.setHandler(rh);
        return context;
      }

Swagger.json没有被喂食swagger ui

1 个答案: