这是我的XML:
<?xml version="1.0" encoding="UTF-8"?>
<NewDataSet>
<xs:schema xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:xs="http://www.w3.org/2001/XMLSchema" id="NewDataSet">
<xs:element msdata:IsDataSet="true" msdata:UseCurrentLocale="true" name="NewDataSet">
<xs:complexType>
<xs:choice maxOccurs="unbounded" minOccurs="0">
<xs:element name="Table1">
<xs:complexType>
<xs:sequence>
<xs:element minOccurs="0" msdata:DateTimeMode="Unspecified" name="MAXTIME" type="xs:dateTime"/>
<xs:element minOccurs="0" name="X" type="xs:string"/>
<xs:element minOccurs="0" name="Y" type="xs:string"/>
<xs:element minOccurs="0" name="Z" type="xs:string"/>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>
<Table1>
<MAXTIME/>
<X>123</X>
<Y>DDo</Y>
<Z>Cri</Z>
</Table1>
</NewDataSet>
我想从上面的xml文件中获取xml架构,但是当我使用
时 XmlReader reader = XmlReader.Create(xmlPath);
XmlSchemaSet schemaSet = new XmlSchemaSet();
XmlSchemaInference schema = new XmlSchemaInference();
schemaSet = schema.InferSchema(reader);
失败了:
The supplied xml instance is a schema or contains an inline schema. This class cannot infer a schema for a schema.
那么我应该如何获得它来获取架构
答案 0 :(得分:0)
使用此:
DataSet dset = new DataSet();
dset.ReadXml("xmlFile.xml",XmlReadMode.IgnoreSchema);
var _schema = dset.GetXmlSchema();