Question

我使用PHP将数据从表插入另一个具有附加列的数据，然后从第一个表中删除该行。但是，我似乎无法使其发挥作用：

ListID   FNAME    LNAME
null      null    null
null      null    null

Answer 1

您需要在选择中包含附加列作为常量，并且您不需要选择周围的VALUE（）。：

public function insertReq($dID, $bphone)
{
        $stmt = $this->conn->prepare("INSERT INTO RequestedDevices(dID, deviceName, Medical, Description, Educational, DevicePicture, bphone) SELECT id, deviceName, Medical, Description, Educational, DevicePicture, ? WHERE id = ? from TABLE NAME )");
        $flag = $stmt->execute(["someAdditionalColumData", "someID"]);
        $stmt1 = $this->conn->prepare("DELETE FROM DEVICE WHERE id= ? ");
        $flag1 = $stmt1->execute(["originalTableID"]);
        if ($flag & flag1) {
            return ADDED;
        } else {
            return NOT_ADDED;
        }
    }

从表中插入另一列PHP

1 个答案: