Question

如何将应用程序作为最顶层的窗口。我在excel中打开了两个excel文件。我关闭第一个文件，然后重新打开它。但我希望第二个文件成为最顶层的窗口。如何在不关闭第二个文件并重新打开的情况下完成该操作。我只需要在win32com中调度即可。

import time, os.path, os
from win32com.client import Dispatch

path1 = 'C:\\Todolist.xls'
path2 = 'C:\\Todolist2.xlsx'

xla = Dispatch("Excel.Application")
xla.DisplayAlerts = False
xla.Visible = True

xl = Dispatch("Excel.Application")
xl.DisplayAlerts = False
xl.Visible = True

wb1= xla.Workbooks.Open(Filename=path1)
wb2= xl.Workbooks.Open(Filename=path2)

wb1.Close()
time.sleep(3) 
wb1= xl.Workbooks.Open(Filename=path1)
#Need to bring wb2 back as the top most window

Answer 1

试试这个

import win32gui

def windowEnumerationHandler(hwnd, windows):
    windows.append((hwnd, win32gui.GetWindowText(hwnd)))

windows = []
win32gui.EnumWindows(windowEnumerationHandler, windows)
for i in windows:
    if "window_heading" in i[1].lower():
        win32gui.ShowWindow(i[0],5)
        win32gui.SetForegroundWindow(i[0])
        break

使应用程序窗口成为最顶层（活动）窗口

1 个答案: