Question

我需要在另一个公共secuanci中执行循环序列并获取每个人和每个状态的数据，我对代码的问题是它不会迭代我提供的数据。当我有空字段时，我需要第二个for-each的帮助，然后我可以使用Word内容控件

XML文件

<?xml version="1.0"?>
<emailList>
  <person>
    <name>name 1</name>
    <email>g@gmail.com</email>
    <status>
        <active>1</active>
        <active>2</active>
        <active>3</active>
    </status>
  </person>
  <person>
    <name>name 2</name>
    <email>n@hotmail.com</email>
    <status>
        <active>4</active>
        <active>5</active>
    </status>
  </person>
</emailList>

XSL文件

<xsl:stylesheet version="1.0">
<html xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xsl:version="1.0">
  <head>
    <title>Email Listing</title>
  </head>
  <body>
    <table>
      <tr>
        <th>Name</th>
        <th>E-mail Address</th>
        <th>Status</th>
      </tr>
      <xsl:for-each select="emailList/person">
        <tr>
          <td><xsl:value-of select="name"/></td>
          <td><xsl:value-of select="email"/></td>
          <td>
            <xsl:for-each select="emailList/person/status">
            <xsl:value-of select="active"/>
            </xsl:for-each>
          </td>
        </tr>
      </xsl:for-each>
    </table>
  </body>
</html>

Answer 1

您的内部xsl:for-each将与外部person相对，即选择<xsl:for-each select="status/active"> <xsl:value-of select="."/> </xsl:for-each>。

尝试将其更改为此...

<xsl:for-each select="status/active"> <xsl:if test="position() > 1">,</xsl:if> <xsl:value-of select="."/> </xsl:for-each>选择当前节点的位置。

如果你想用逗号分隔值，你可以这样做....

xsl:for-each

更好的是，升级到XSLT 2.0并完全取消<td> <xsl:value-of select="status/active" separator="," /> </td> ..

String[][] table;
JsonParser parser = new JsonParser();
JsonObject obj = parser.parse(document.text()).getAsJsonObject();
JsonArray array = obj.get("movimientos").getAsJsonArray();
table = new String[3][array.size()];
for (int i = 0; i < array.size(); i++) {
    JsonObject element = array.get(i).getAsJsonObject();
    table[0][i] = element.get("fechaDatetime").getAsString();
    table[1][i] = element.get("movimiento").getAsString();
    table[2][i] = element.get("ubicacion").getAsString();
}

Answer 2

<xsl:template match="/">
    <html>
        <head>
            <title>Email Listing</title>
        </head>
        <body>
            <table>
                <tr>
                    <th>Name</th>
                    <th>E-mail Address</th>
                    <th>Status</th>
                </tr>
                <xsl:for-each select="emailList/person">
                    <tr>
                        <td><xsl:value-of select="name"/></td>
                        <td><xsl:value-of select="email"/></td>
                        <td>
                            <xsl:for-each select="status">
                                <xsl:value-of select="active"/>
                            </xsl:for-each>
                        </td>
                    </tr>
                </xsl:for-each>
            </table>
        </body>
    </html>
    </xsl:template>

XSL：每个迭代数据中的每个内部

2 个答案: