这个问题可能已被提出，但我有点迷失了。 这是代码：
<form class="ui form attached fluid loading segment" onsubmit="return contact(this)">
<div class="field">
<label>Preferred Tour</label>
<div class="field">
<?php
$conn=mysqli_connect('####','####','####','####');
echo '<select required id="tourInfo">';
echo '<option value="" selected disabled>--Preferred Tour--</option>';
$db = mysqli_query($conn, "SELECT `id`,`tourprice`,`tourname` FROM `available_tours`");
while ($d=mysqli_fetch_assoc($db)) {
echo "<option value=".$d['id']." id=".$d['tourname']. " data-price=".$d['tourprice'].">".$d['tourname']."</option>";
}
echo "</select>";
?>
</div>
</div>
<div class="field" id="hiddenTortu" style="display: none;">
<label>Attention</label>
<div class="ui icon">
<p><b>The minimum of people for this tour is 5, less than 5 the tour is not realisable</b></p>
</div>
</div>
<div class="field">
<label>Available Time</label>
<div class="field">
<?php
$conn=mysqli_connect('####','####','####','####');
echo '<select name="gender" required id="timeInfo">';
echo '<option value="" selected disabled>--Preferred Time--</option>';
$db = mysqli_query($conn, "SELECT `time_real` FROM `available_time`");
while ($d=mysqli_fetch_assoc($db)) {
echo "<option value=".$d['time_real'].">".$d['time_real']."</option>";
}
echo "</select>";
?>
</div>
</div>
<div class="two fields">
<div class="field" id="pax">
<label>Please specify the number of People according to the perred tour selection</label>
这里根据游览选择启动以下脚本的问题我尝试设置最小值和最大值，以便用户无法为游览中的人选择更多号码。 问题是当用户选择第一个选项，然后意识到最佳选项是另一个选项时，当他/她做另一个选择时，使用附加的jQuery创建的输入仍然存在并且由于新选择创建新输入。 意图是如果用户选择选项1，则输入附加根据选项1出现，但如果用户后悔并且更喜欢选项2，则选项1的输入消失，并且根据选项输入新输入对于整个if条件，出现2等等。
<script>
$(document).ready(function(){
$('#tourInfo').on('change', function() {
if ( this.value == '1')
{
$("#pax").append($('<input placeholder="Number of People" type="number" id="peopleInfo" min="1" max="2" value="1" required>'));
(function ($) {
$.fn.restrict = function () {
return this.each(function(){
if (this.type && 'number' === this.type.toLowerCase()) {
$(this).on('change', function(){
var _self = this,
v = parseFloat(_self.value),
min = parseFloat(_self.min),
max = parseFloat(_self.max);
if (v >= min && v <= max){
_self.value = v;
}
else {
_self.value = v < min ? min : max;
}
});
}
});
};
})(jQuery);
$('#peopleInfo').restrict();
}
else if (this.value == '2')
$("#pax").append($('<input placeholder="Number of People" type="number" id="peopleInfo" min="3" max="5" value="3" required>'));
(function ($) {
$.fn.restrict = function () {
return this.each(function(){
if (this.type && 'number' === this.type.toLowerCase()) {
$(this).on('change', function(){
var _self = this,
v = parseFloat(_self.value),
min = parseFloat(_self.min),
max = parseFloat(_self.max);
if (v >= min && v <= max){
_self.value = v;
}
else {
_self.value = v < min ? min : max;
}
});
}
});
};
})(jQuery);
$('#peopleInfo').restrict();
}
else if (this.value == '3')
{
$("#pax").append($('<input placeholder="Number of People" type="number" id="peopleInfo" min="6" max="15" value="6" required>'));
(function ($) {
$.fn.restrict = function () {
return this.each(function(){
if (this.type && 'number' === this.type.toLowerCase()) {
$(this).on('change', function(){
var _self = this,
v = parseFloat(_self.value),
min = parseFloat(_self.min),
max = parseFloat(_self.max);
if (v >= min && v <= max){
_self.value = v;
}
else {
_self.value = v < min ? min : max;
}
});
}
});
};
})(jQuery);
$('#peopleInfo').restrict();
}...
...});
};
})(jQuery);
$('#peopleInfo').restrict();
}
});
});
</script>
</div>
<div class="field">
<label><br>Date of Tour</label>
<input type="text" readonly required id="tourDate" class="datepicker-here form-control" placeholder="ex. August 03, 1998">
</div>
</div>
<div style="text-align:center">
<div>
<label>Ensure all details have been filled correctly</label>
</div>
<button class="ui green submit button">Submit Details</button>
</div>
</form>
</div>
请你帮帮我!!!
先谢谢。
答案 0 :(得分：0)
使用id pax从div内部移出脚本，然后 在附加：
之前，使用id pax清除元素的html //Using JQuery
$('#pax').html('');