我有一段代码在表格中搜索某个短语。找到短语后,它会将当前单元格的innerHTML返回到页面顶部附近的div。
我遇到的问题是:
除非被搜索的短语包含任何特殊字符(括号和&符号等),否则代码可以完美地运行。我尝试将短语从“Western & Central"
修改为"Western & Central"
但遗憾的是代码仍无法找到该短语。
下面是代码:
// Function for searching tables for specific map/device combination.
function findMap(map, device)
{
var flag = false; // to check if the map has been found yet
// Add <strong> tags to map string so it is easier to search for
var mapstring = "<strong>" + map;
var map_regex = new RegExp( mapstring,'i');
// create array of tables
var tables = document.getElementsByTagName('table');
for (var t = 2; t < tables.length; t++)
{
// create array of rows
var tablerows = tables[t].rows;
for (var r = 2; r < tablerows.length; r++)
{
currentRow = tablerows[r];
// Check if current row contains map name
if (currentRow.innerHTML.match(map_regex))
{
var tablecells = currentRow.cells;
for (var c = 1; c < tablecells.length; c++)
{
currentCell = tablecells[c];
// Check if current cell contains device name
if (currentCell.innerHTML.match(device))
{
document.getElementById("boxy2").innerHTML = currentCell.innerHTML;
flag = true;
}
if (flag == true) return;
}
if (flag == true) return;
// search for x20 if 920 was not found etc
if (device == "910")
device = "x10";
else if (device == "920")
device = "x20";
else if (device == "930")
device = "x30";
else if (device == "940")
device = "x40";
else if (device == "950")
device = "x50";
// search cells again
for (var c = 1; c < tablecells.length; c++)
{
currentCell = tablecells[c];
if (currentCell.innerHTML.match(device))
{
document.getElementById("boxy2").innerHTML = currentCell.innerHTML;
flag = true;
}
if (flag == true) return;
}
if (flag == true) return;
}
if (flag == true) return; else { document.getElementById("boxy2").innerHTML="Map not available on this device."; }
}
}
}
非常感谢任何有关此事的帮助!
答案 0 :(得分:2)
由于您只是想检查特定字符串是否存在,我认为如果您使用indexOf而不是RegExps,您的解决方案可能会更强大。
使用RegExps,如果您要查找特殊字符,例如[
或]
或(
或)
,则需要将其转义,这只是另一层我觉得你不需要介绍的复杂性。
因此,请尝试替换正则表达式,例如......
if (currentRow.innerHTML.match(map_regex))
有了......
if (currentRow.innerHTML.indexOf(mapString)!=-1)