我坚持在Angular 2中使用Array.map返回一个值 那我在这里错过了什么?
export class TabsPage {
@ViewChild(SuperTabs) superTabs: SuperTabs;
public rootTab: string = 'ProductListPage';
public categories: Array<any>;
public collection_id: number;
public selectedindex: any;
private getArrayIndex(source, target) {
source.map((element, index) => {
if (element.attrs.collection_id === target) {
// Returns the Value i need
console.log('i: ', index);
return index;
}
});
}
constructor(
public navCtrl: NavController,
public navParams: NavParams,
public shopifyClientProvider: ShopifyClientProvider,
private superTabsCtrl: SuperTabsController,
) {
this.categories = navParams.get('collections');
this.collection_id = navParams.get('collection_id');
this.selectedindex = this.getArrayIndex(this.categories, navParams.get('collection_id'));
// Returns undefined
console.log('Index ', this.selectedindex);
}
}
答案 0 :(得分:2)
我知道这个问题已经回答了,但我有一个解决方案。
.ts文件代码
private getArrayIndex(source, target) {
let indx = -1;
source.map((element, index) => {
if (element.attrs.collection_id === target) {
// Returns the Value i need
console.log('i: ', index);
indx = index;
}
});
return indx;
}
答案 1 :(得分:1)
您可以使用findIndex()以非常短的顺序执行此操作:
我不确切知道你的数据是什么样的,但给出了一个数组:
const target = 2;
const source = [
{
attrs: {
collection_id: 1
}
},
{
attrs: {
collection_id: 2
}
},
{
attrs: {
collection_id: 3
}
},
];
const index = source.findIndex(element => element.attrs.collection_id === target);
将为索引返回1
。如果未找到索引,则将返回-1
。
Plunkr:https://plnkr.co/edit/5B0gnREzyz6IJ3W3
希望能帮到你。
答案 2 :(得分:0)
看起来Typescript打破了回报。通过此修改,我获得了所需的值:
private getArrayIndex(source, target) {
let found: number;
source.map((element, index) => {
if (element.attrs.collection_id === target) {
console.log('i: ', index);
found = index;
}
});
return found;
}