Question

一些开发人员使用Laravel和Datatables制作了一个PHP软件。当我看到应用程序生成的数据库查询时，我发现效率非常低。示例（涉及列的列表从一个软件功能更改为另一个软件功能）：

 select count(*) as aggregate from (select '1' as [row_count] from [assignments]
  left join [jobs] on [assignments].[id] = [jobs].[name] 
  left join [categories] on [categories].[id] = [jobs].[vol_cat_type]
   where ([assignments].[id] LIKE '%XYZ%' or [assignments].[person_id] LIKE '%XYZ%' or 
    (select count(1) from [people] where [assignments].[person_id] = [people].[person_id] and [people].[name_title] LIKE '%XYZ%') >= 1 or 
    (select count(1) from [people] where [assignments].[person_id] = [people].[person_id] and [people].[first_name] LIKE '%XYZ%') >= 1 or 
    [assignments].[title] LIKE '%XYZ%' or 
    (select count(1) from [people] where [assignments].[person_id] = [people].[person_id] and [people].[gender] LIKE '%XYZ%') >= 1 or 
    (select count(1) from [states_master] where [states_master].[identity] = [assignments].[current_state] and [states_master].[name] LIKE '%XYZ%') >= 1 or
        [assignments].[updated_datetime] LIKE '%XYZ%' or
        (select count(1) from [people] where [assignments].[person_id] = [people].[person_id] and [people].[nationality] LIKE '%XYZ%') >= 1 or 
    (select count(1) from [people] where [assignments].[person_id] = [people].[person_id] and [people].[place_of_birth] LIKE '%XYZ%') >= 1 or 
    (select count(1) from [people] where [assignments].[person_id] = [people].[person_id] and [people].[civil_status] LIKE '%XYZ%') >= 1 or 
    (select count(1) from [people] where [assignments].[person_id] = [people].[person_id] and [people].[email] LIKE '%XYZ%') >= 1 or 
    (select count(1) from [people] where [assignments].[person_id] = [people].[person_id] and [people].[date_of_birth] LIKE '%XYZ%') >= 1 or 
    (select count(1) from [people] where [assignments].[person_id] = [people].[person_id] and [people].[nationality2] LIKE '%XYZ%') >= 1
      or (select count(1) from [people] where [assignments].[person_id] = [people].[person_id] and [people].[skype] LIKE '%XYZ%') >= 1))
       count_row_table

涉及的表很大，这些查询不仅需要20-30秒才能执行，而且还会影响服务器的一般性能。我不喜欢的是许多LIKE应用于所有列，特别是那些应用于非字符串的列（如上次修改日期）。我的建议是：

1）对于所有非字符串：数字使用=而不是LIKE，使用性别M / F，布尔值等单字符代码

2）配置Microsoft SQL Server中包含的全文搜索，并写入CONTAINS（列，＆＃39; XYZ＆＃39;）而不是LIKE

开发人员的反对意见是Laravel和Datatables产生了这些查询，我们无能为力。

是否可以配置Laravel和Datatables，当然不需要更改库代码，为每个列指定是使用LIKE，=还是CONTAINS？

Answer 1

Eloquent通常用于创建更简单的模型查询。

对于更复杂的SQL查询，请使用查询构建器。

这是有关如何使用它的文档中的一个示例。

$users = DB::table('users')
                     ->select(DB::raw('count(*) as user_count, status'))
                     ->where('status', '<>', 1)
                     ->groupBy('status')
                     ->get();

如果您愿意，也可以使用原始SQL。

$results = DB::select('select * from users where id = :id', ['id' => 1]);

参考文献：

https://laravel.com/docs/5.6/queries

https://laravel.com/docs/5.6/database#running-queries

Laravel，Datatables，低效查询

1 个答案: