Question

这是我的字符串，我必须从中提取网址

s = "'0352442':{url:'https://www.riteaid.com/shop/nexium-24hr-42-ct-capsules-0352442'},'0370009':{url:'https://www.riteaid.com/shop/rite-aid-pharmacy-epsom-salt-first-aid-6-lb-2-72-kg-0370009'},'0303249':{url:'https://www.riteaid.com/shop/huggies-natural-care-unscented-baby-wipes-soft-pack-56-count-0303249'},'0398568':{url:'https://www.riteaid.com/shop/rite-aid-sterile-pads-4-x4-25-ea-0398568'},}"

我尝试过的代码到现在才打印

urls = re.findall('https?://(?:[-\w.]|(?:%[\da-fA-F]{2}))+', s)

但它只会打印此网址的重复

    ['https://www.riteaid.com']

Answer 1

正如你所提到的字母像字符串一样，你必须使用正则表达式来处理你的特殊情况。

s = "'0352442':{url:'https://www.riteaid.com/shop/nexium-24hr-42-ct-capsules-0352442'},'0370009':{url:'https://www.riteaid.com/shop/rite-aid-pharmacy-epsom-salt-first-aid-6-lb-2-72-kg-0370009'},'0303249':{url:'https://www.riteaid.com/shop/huggies-natural-care-unscented-baby-wipes-soft-pack-56-count-0303249'},'0398568':{url:'https://www.riteaid.com/shop/rite-aid-sterile-pads-4-x4-25-ea-0398568'},}"

urls = re.findall(r"url:'(https?://.*?)'}", s)

result:
['https://www.riteaid.com/shop/nexium-24hr-42-ct-capsules-0352442',
 'https://www.riteaid.com/shop/rite-aid-pharmacy-epsom-salt-first-aid-6-lb-2-72-kg-0370009',
 'https://www.riteaid.com/shop/huggies-natural-care-unscented-baby-wipes-soft-pack-56-count-0303249',
 'https://www.riteaid.com/shop/rite-aid-sterile-pads-4-x4-25-ea-0398568']

<强>解释

网址：＆＃39;（http ：文字字符串

s？：可选的字面字符＆＃34; s＆＃34;

。*？：不贪心任何角色。

＆＃39;}：：文字字符串

Answer 2

如果您必须使用当前示例的正则表达式在{url:'和'}之间进行匹配，则可以使用肯定的lookbehind (?<=和积极的预测{{1}并使用与(?=一次或多次匹配的否定字符类[^']+来匹配网址。

(?<={url:')[^']+(?='})

Demo

您还可以减少对示例数据的限制，并忽略前导'和尾随{：

(?<=url:')[^']+(?=')

用于从字符串

2 个答案: