Question

我有一个包含customer_id，customer_name，month_day，month，total_sales的表。数据类似于以下方式

customer_id     customer_name   month_day   month       total_sales
   1            ravi            2           Feb         479892.901
   2            arun            7           Aug         889390.709
   3            goutham         6           Sep         791831.561
   4            naveen          8           Sep         797413.558

此处total_sales的平均值为739632.18，其5％为36981.6，总数为776613.78。我想在9月份将这个总数介于776613.78和739632.18之间。

Answer 1

你需要这样的东西：

SELECT customer_id FROM a 
WHERE month_day = 6 and month = 'Apr' --Date and Month filter
and total_sales > (SELECT (AVG(total_sales)*1.05) FROM a WHERE month_day = 6 and month = 'Apr');

我有点困惑，为什么当这是销售表时你没有相同的customer_id

这是一个查询，以防这是customer_id不是pk

的订单交易

SELECT customer_id FROM a 
WHERE month_day = 6 and month = 'Apr' 
GROUP BY customer_id
HAVING SUM(total_sales) > (SELECT (AVG(total_sales)*1.05) FROM a WHERE month_day = 6 and month = 'Apr');

希望得到帮助

Answer 2

这对我来说不是很清楚，但也许这个？

SELECT *
FROM sales,
  (SELECT avg(total_sales) AS avgval
   FROM sales
   WHERE month = 'Sep') tabavg
WHERE month = 'Sep'
      AND day = '1'
      AND total_sales > tabavg.avgval
      AND total_sales < tabavg.avgval * 1.05;

如何编写SQL查询以查找超过平均值的百分比？

2 个答案: