Question

我是Nodejs和typescript的新手。我有两个以下的jsons：

json1 = 
{
    "201809": 2,
    "metric": "headcount",
    "quarter1": 60,
    "careerLevelsGroups": [{
        "201809": 2,
        "quarter1": 60,
        "careerLevels": [{
                "201809": 2,
                "careerId": "careerId1",
                "quarter1": 60,
            },
            {
                "201809": 2,
                "careerId": "careerId2",
                "quarter1": 50,
            }
        ]
    }]
}

json2 = 
    {
        "201809": 3,
        "metric": "headcount",
        "quarter1": 100,
        "careerLevelsGroups": [{
            "201809": 7,
            "quarter1": 40,
            "careerLevels": [{
                    "201809": 9,
                    "careerId": "careerId1",
                    "quarter1": 30,
                },
                {
                    "201809": 8,
                    "careerId": "careerId2",
                    "quarter1": 30,
                }
            ]
        }]
    }

我想将与相同键相关联的所有数值相加并生成一个json，其总和值为json1和json2。

result = 
{
        "201809": 5,
        "metric": "headcount",
        "quarter1": 160,
        "careerLevelsGroups": [{
            "201809": 9,
            "quarter1": 100,
            "careerLevels": [{
                    "201809": 11,
                    "careerId": "careerId1",
                    "quarter1": 90,
                },
                {
                    "201809": 10,
                    "careerId": "careerId2",
                    "quarter1": 80,
                }
            ]
        }]
    }

我正在尝试使用循环，但是我有太多这样的元素需要总结，所以请你建议在Node.js中使用更优化的方法

Answer 1

我整理了一个// send command method STRING szCmdPath, szCmdLine ; szCmdPath = "C:\\WINDOWS\\system32\\cmd.exe"; szCmdLine = "/c wslconfig /l > D:\\output.txt"; LaunchAppAndWait(szCmdPath, szCmdLine, WAIT);函数，该函数使用递归来处理JSON对象的成员。如果它检测到combine()它将它组合在一起。如果它检测到"number"，则会应用递归来搜索其中的更多"object"或"number"。对于任何其他类型（例如"object"），它只是将值保留为原样。

"string"

运行脚本会产生所需的输出。它应该是一个简单的执行，迭代一系列这些JSON对象来生成所需的结果。

javascript JSON：将两个或多个json相加，只使用相同键的数值

1 个答案: